True, because his model has the electrons in the sphere of the atom, Thomson’s model was called the “Plum Pudding” model because it was popular and relatable at his time.
Hope this helps!! ^v^
Answer:
84.30 mm Hg
Explanation:
In 100 cm³ of solution we have: 40 cm³ C6H6 and 60 cm³ CCl4. Given the densities we can calculate their masses and number of moles, and since by Raoult´s law
Ptotal = XAPºA + XBPºB
where XA= mol fraction =na/(na +nb) and PºA vapor pressure pure of pure component A
m C6H6 = 40 cm³ x 0.87865 g/cm³ = 35.146 g
mol C6H6 = 35.146 g/ 78.11 g/mol = 0.45 mol
mass CCl4 = 60 cm³ x 1.5940 g/cm³ = 95.640 g
mol CCl4 = 95.640 g / 153.82 g/mol = 0.62 mol
mol tot = 1.07
XC6H6 = 0.45/ 1.07 = 0.42 XCCl4 = 0.62/1.07 =0.58
Ptot (mmHg) = 0.42 x 74.61 + .58 x 91.32 = 84.30 mmHg
Answer:
<em><u>i think grass hopper</u></em>
Explanation:
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Answer:
1.52V
Explanation:
Oxidation half equation:
2Al(s)−→2Al^3+(aq) + 6e
Reduction half equation
3Sn2^+(aq) + 6e−→3Sn(s)
E°cell= E°cathode - E°anode
E°cathode= −0.140 V
E°anode= −1.66 V
E°cell=-0.140-(-1.66)
E°cell= 1.52V
Answer:
How many grams Iron(II) Sulfide in 1 mol? The answer is 87.91. We assume you are converting between grams Iron(II) Sulfide and mole. You can view more details on each measurement unit: molecular weight of Iron(II) Sulfide or mol The molecular formula for Iron(II) Sulfide is FeS. The SI base unit for amount of substance is the mole.
Explanation:
