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3 years ago

How is human activity affected by sinkholes

Chemistry

1 answer:

tamaranim1 [39]3 years ago

8 0

The effects of sinkholes vary based on where and how they were formed.

When naturally formed on land, they will change the topography of the surroundings, cause nothing but minor issues, if any issue at all.

When formed on highly populated areas, though, they can cause a lot of damage to humans and properties in the region. Damage caused to the base of a building might be a very serious problem.

Toxic chemicals can also come up through sinkholes.

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MAJOR, PLEASE HELP, BRAINEST IF CORRECT

Vanyuwa [196]

Answer:

B and C

Explanation:

6 0

3 years ago

Can someone help me by giving me the formula of determining the amount of energy used in a reaction?

Vlada [557]

Q=mc(deltaT)
Q is the amount of energy which you are looking for
M is the mass which you can find
C is the specific heat of water which is 4.18 J/gC
DeltaT is the change in temperature which you can find.

To find the mass, first you must know that the density of water is 1g/mL, meaning that 200 mL has a mass of 200 g. This means that to find the total mass (m in the equation) all you need to do is add the mass of water and NaOH.

200 g + 2.535 g=202.535 g.

To find deltaT you would need to take the final temperature minus the initial temperature.

27.8C-24.2C=3.6C

Then these values can be substituted into the equation:

q=(202.635g)(4.18J/gC)(3.6C)
Q=3049.25 J

Technically this should be rounded off to 1 significant figure (200 mL only had 1), but ignoring signficiant figure rules this should be correct. Also, sometimes other units like calories or kJ may be asked for, meaning that a conversion or alternate c value would be used.

5 0

3 years ago

What is the oxidation number for s in s2o4?

hoa [83]

The oxidation number of O is -2 and there's 4 of them so the total is -8. Since it's a molecule the sum of the oxidation numbers of the atoms must equal 0. If 4 oxygen atoms have an oxidation number of -8 then the two S atoms must is +8 to equal 0 so the oxidation number of the S is 8/2 = +4

3 0

3 years ago

Stuck stupid science homework. anyone know answers?

Veronika [31]

The charge of a Rb ion would be +1

7 0

3 years ago

If you feed 100 kg of N2 gas and 100 kg of H2 gas into a

torisob [31]

Answer : The mass of ammonia produced can be, 121.429 k

Solution : Given,

Mass of $N_2$ = 100 kg = 100000 g

Mass of $H_2$ = 100 kg = 100000 g

Molar mass of $N_2$ = 28 g/mole

Molar mass of $H_2$ = 2 g/mole

Molar mass of $NH_3$ = 17 g/mole

First we have to calculate the moles of $N_2$ and $H_2$ .

$\text{ Moles of }N_2=\frac{\text{ Mass of }N_2}{\text{ Molar mass of }N_2}=\frac{100000g}{28g/mole}=3571.43moles$

$\text{ Moles of }H_2=\frac{\text{ Mass of }H_2}{\text{ Molar mass of }H_2}=\frac{100000g}{2g/mole}=50000moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$N_2+3H_2\rightarrow 2NH_3$

From the balanced reaction we conclude that

As, 1 mole of $N_2$ react with 3 mole of $H_2$

So, 3571.43 moles of $N_2$ react with $3571.43\times 3=10714.29$ moles of $H_2$

From this we conclude that, $H_2$ is an excess reagent because the given moles are greater than the required moles and $N_2$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $NH_3$

From the reaction, we conclude that

As, 1 mole of $N_2$ react to give 2 mole of $NH_3$

So, 3571.43 moles of $N_2$ react to give $3571.43\times 2=7142.86$ moles of $NH_3$

Now we have to calculate the mass of $NH_3$

$\text{ Mass of }NH_3=\text{ Moles of }NH_3\times \text{ Molar mass of }NH_3$

$\text{ Mass of }NH_3=(7142.86moles)\times (17g/mole)=121428.62g=121.429kg$

Therefore, the mass of ammonia produced can be, 121.429 kg

6 0

3 years ago