Answer:
A...................................
<span>The solubility of KClO</span>₃ : ( 10.1 / 100 g water ) at 30ºC
10.1 g ------------ 100 g ( H₂O )
? g ------------- 100 g ( H₂O )
Mass of KClO₃ :
100 * 10.1 / 100
1010 / 100 = 10.1 g of KClO₃
hope this helps!
Answer:
It is difficult, if not impossible, to heat a solid above its melting point because the heat that ... in a solid are packed in a regular structure that is characteristic of that particular substance.
<h3>#carryONlearning </h3>