9514 1404 393
Answer:
80.5°
Step-by-step explanation:
The applicable trig function is the tangent.
Tan = Opposite/Adjacent
In this scenario, the side opposite the angle is the tower height, 324 m. The side adjacent is the distance to the tower, 54 m. Then the angle α is related by ...
tan(α) = 324/54
The value of the angle with this tangent is found using the arctangent function:
α = arctan(324/54) ≈ 80.5°
She should set her binoculars to 80.5°.
Answer:
323 mod 5 = 3
−323 mod 5 = -3
327 mod 3 = 0
(64 * (-67) + 201) mod 7 = 6
(38^12) mod 6 = 4
(38^12) mod 3 = 1
Step-by-step explanation:
The modulo operation looks for remainders from the quotients. In order to find them, divide the whole number by the mod number. Then take just the decimal after the whole answer and multiply it by the mod number.
<u>323 mod 5</u>
323/5 = 64.6
.6 * 5 = 3
<u>−323 mod 5</u>
323/5 = -64.6
-.6 * 5 = -3
<u>327 mod 3</u>
327/5 = 109
0 * 3 = 0
<u>(64 * (-67) + 201) mod 7</u>
64 * -67 = -4288 + 201 = 4087
4087/7 = 583.85714
.85714 * 7 = 6
<u>(38^12) mod 6</u>
38^12 = 9.07x10^18
9.07x10^18/6 = 1510956318082499242.6666667
.666667 * 6 = 4
<u>(38^12) mod 3</u>
38^12 = 9.07x10^18
9.07x10^18/3 = 3021912636164998485.333333
.3333333 * 3 = 1
Answer:
y = ![\frac{96}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B96%7D%7B5%7D)
Step-by-step explanation:
given that y and x are proportional then the equation relating them is
y = kx ← k is the constant of proportionality
to find k use the given condition y = 12 when x = 5
k =
= ![\frac{12}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B12%7D%7B5%7D)
y =
x ← equation of proportionality
when x = 8, then
y =
× 8 = ![\frac{96}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B96%7D%7B5%7D)
Answer:
36.2
Step-by-step explanation:
Assuming that the dotted line is a perpendicular bisector, we can say that it splits the side that is 30 units long into 2 sets of 15 units. Then, we can use the pythaogrean theorem to solve (Leg A is 33 and Leg B: 15). a^2+b^2=c^2
33^2+15^2=c^2
1089+225=c^2
1314=c^2
Square root of 1314 = square root of c^2
36.2 aapproximately c