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devlian [24]
3 years ago
12

Please help me with this math question

Mathematics
1 answer:
Dmitriy789 [7]3 years ago
3 0

Answer:

6cm ; 22cm

Step-by-step explanation:

Given that:

Total Length, AD = 28cm

AB =x cm

BC = (x +5)cm

CD = 2x - 1 cm

4x + 4 = 28

4x = 28 - 4

4x = 24

x = 24 / 4

x = 6cm

The length of BD

BD = BC + CD

BD = (x + 5) + (2x - 1)

x = 6

BD = (6 + 5) + (2(6) - 1)

BD = 11 + (12 - 1)

BD = 11 + 11

BD = 22 cm

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What is the probability of spinning the spinner and it landing on a VOWEL?
Olegator [25]

There are six sections in the spinner below. There are two vowel sections. Two sixths is the first representation.

1. Turn Two Sixths Into A Decimal.

= 2 ÷ 6

= 0.33333333333.....

2. Simplify.

0.33

3. Turn Into Percentage

33%

33% Of The Spinner Is Vowels

6 0
3 years ago
How do you write “twice a number less than 3 is 17” as an equation?
ki77a [65]

Answer:

2 x 3 < 17

Step-by-step explanation:

Greater than and/or less than step by step equasion.

4 0
3 years ago
Identify the radius and center.<br><br> x^2 + y^2 - 2x + 4y - 11 = 0
miss Akunina [59]
<h2>Hello!</h2>

The answer is:

Center: (1,-2)

Radius: 4 units.

<h2>Why?</h2>

To solve the problem, using the given formula of a circle, we need to find its standard equation form which is equal to:

(x-h)^{2}+(y-k)^{2}=r^{2}

Where,

"h" and "k"are the coordinates of the center of the circle and "r" is its radius.

So, we need to complete the square for both variable "x" and "y".

The given equation is:

x^2+y^2-2x+4y-11=0

So, solving we have:

x^2+y^2-2x+4y=11

(x^2-2x+(\frac{2}{2})^{2} )+(y^2+4y+(\frac{4}{2})^{2})=11+(\frac{2}{2})^{2} +(\frac{4}{2})^{2}\\\\(x^2-2x+1)+(y^2+4y+4)=11+1+4\\\\(x^2-1)+(y^2+2)=16

(x^2-1)+(y^2-(-2))=16

Now, we have that:

h=1\\k=-2\\r=\sqrt{16}=4

So,

Center: (1,-2)

Radius: 4 units.

Have a nice day!

Note: I have attached a picture for better understanding.

5 0
4 years ago
If a hurricane was headed your way, would you evacuate? The headline of a press release issued January 21, 2009 by the survey re
Nikolay [14]

Answer:

The 98% confidence interval for population proportion of people who refuse evacuation is {0.30, 0.33].

Step-by-step explanation:

The sample drawn is of size, <em>n</em> = 5046.

As the sample size is large, i.e. <em>n</em> > 30, according to the Central limit theorem the sampling distribution of sample proportion will be normally distributed with mean \hat p and standard deviation \sqrt{\frac{\hat p (1-\hat p)}{n} }.

The mean is: \hat p=0.31

The confidence level (CL) = 98%

The confidence interval for single proportion is:

CI_{p}=[\hat p-z_{(\alpha /2)}\times\sqrt{\frac{\hat p (1-\hat p)}{n} },\ \hat p+z_{(\alpha /2)}\times\sqrt{\frac{\hat p (1-\hat p)}{n} }]

Here z_{(\alpha /2)} = critical value and <em>α </em>= significance level.

Compute the value of <em>α</em> as follows:

\alpha =1-CL\\=1-0.98\\=0.02

For <em>α</em> = 0.02 the critical value can be computed from the <em>z</em> table.

Then the value of z_{(\alpha /2)} is ± 2.33.

The 98% confidence interval for population proportion is:

CI_{p}=[\hat p-z_{(\alpha /2)}\times\sqrt{\frac{\hat p (1-\hat p)}{n} },\ \hat p+z_{(\alpha /2)}\times\sqrt{\frac{\hat p (1-\hat p)}{n} }]\\=[0.31-2.33\times \sqrt{\frac{0.31\times(1-0.33)}{5046} },\ 0.31+2.33\times \sqrt{\frac{0.31\times(1-0.33)}{5046} } ]\\=[0.31-0.0152,\ 0.31+0.0152]\\=[0.2948,0.3252]\\\approx[0.30,\ 0.33]

Thus, the 98% confidence interval [0.30, 0.33] implies that there is a 0.98 probability that the population proportion of people who refuse evacuation is between 0.30 and 0.33.  

7 0
3 years ago
Please help me out with this
ra1l [238]
Just subtract them and you get 16,700 hope this helps
6 0
4 years ago
Read 2 more answers
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