Let, Number of Hours in Library = x
Number of Hours in babysitting = y
Inequality would be: x + y = 30 ;
& 8x + 6y ≥ 200
b) Solving: Multiply first equation by 6,
6x + 6y ≥ 180
Subtract it from 2nd equation,
2x ≥ 20
x ≥ 10
Now, substitute it in 1st equation,
10 + y = 30
y = 20
Your Answer would be (10, 20)
x - value is lesser or equal to 10, so it would move to left (decreasing direction)!
Hope this helps!
Answer:it the 3rd one
Step-by-step explanation:
I done this
I believe you meant "why is the number of shifts multiplied by approximately 4.5 to obtain the total number of operators required to run the plant"
Answer and Explanation:
There are 3 shifts per day, 49 weeks per year and 5 shifts per operator per week
To get total number of operators required to run the plant, we multiply number of shifts in a year by number if operators per shift.
49 weeks×5 shifts= 245 shifts per operator per year
365×3 shifts= 1095 shifts per year
1095/245=4.5 operators per shift
total number of operators required to run the plant(per day) = 4.5×3= 13.5 approximately 14
total number of operators required to run the plant(per year) =4.5×1095=4927.5 approximately 4928
20.90 would be the item before tax. To get the amount of tax, I multiplied 20 by 0.05 and subtracted that amount from 22
To solve for proportion we make use of the z statistic.
The procedure is to solve for the value of the z score and then locate for the
proportion using the standard distribution tables. The formula for z score is:
z = (X – μ) / σ
where X is the sample value, μ is the mean value and σ is
the standard deviation
when X = 70
z1 = (70 – 100) / 15 = -2
Using the standard distribution tables, proportion is P1
= 0.0228
when X = 130
z2 = (130 – 100) /15 = 2
Using the standard distribution tables, proportion is P2
= 0.9772
Therefore the proportion between X of 70 and 130 is:
P (70<X<130) = P2 – P1
P (70<X<130) = 0.9772 - 0.0228
P (70<X<130) = 0.9544
Therefore 0.9544 or 95.44% of the test takers scored
between 70 and 130.
