PLZ HELP! The number of chips of different colors in Vicky's bag is shown below:

Mathematics

2 answers:

anastassius [24]3 years ago

3 0

The answer is A. 5/25 X5/25 =25/625 if I'm wrong I'm sorry

defon3 years ago

3 0

I believe the answer is A, 5/25X5/25 because she replaced the chip

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We are again studying the times required to solve two elementary math problems. Suppose we ask four students to attempt both Pro

KiRa [710]

Answer:

(-16.494 ; -3.506)

Step-by-step explanation:

student Prob A Prob B difference, d (A-B)

1 20 35____ - 15

2 30 40 ___ - 10

3 15 20 ___ - 5

4 40 50 __ - 10

Difference, d = -15, -10, -5, -10

Xd = Σd/ n = - 40 / 4 = - 10

Standard deviation of d ; Sd = 4.082

The confidence interval for the difference is given as :

Xd ± Tcritical*(Sd/√n)

Tcritical at 95%; df = n - 1 ; 4 - 1 = 3

Tcritical(0.05, 3)). = 3.182

C.I = -10 ± 3.182(4.082/√4)

C.I = -10 ± 6.494462

C. I = (-16.494 ; -3.506)

6 0

3 years ago

Which is greater 0.1 or 3.7

lara31 [8.8K]

Answer:

3.7

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

The physical plant at the main campus of a large state university receives daily requests to replace fluorescent light bulbs. Th

ankoles [38]

We have been given that the distribution of the number of daily requests is bell-shaped and has a mean of 38 and a standard deviation of 6. We are asked to find the approximate percentage of lightbulb replacement requests numbering between 38 and 56.

First of all, we will find z-score corresponding to 38 and 56.

$z=\frac{x-\mu}{\sigma}$

$z=\frac{38-38}{6}=\frac{0}{6}=0$

Now we will find z-score corresponding to 56.

$z=\frac{56-38}{6}=\frac{18}{6}=3$

We know that according to Empirical rule approximately 68% data lies with-in standard deviation of mean, approximately 95% data lies within 2 standard deviation of mean and approximately 99.7% data lies within 3 standard deviation of mean that is $-3\sigma\text{ to }3\sigma$ .