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bearhunter [10]
3 years ago
6

Ocean waves are moving east toward a small island. Which statement is correct about the behavior of the waves?

Physics
2 answers:
PSYCHO15rus [73]3 years ago
6 0
<h3>(A) </h3>

The waves will diffract around the island and converge on the opposite side.

Assoli18 [71]3 years ago
4 0

Answer: Option (1)

Explanation: Waves in the ocean, travelling in a particular direction has the property to get diffracted, on hitting an isolated object or a small island. This means that waves undergoes bending through the edge of an island and subsequently gets mix up on their opposite side.

Hence, the correct answer is option (1).

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the term used to measure a change in speed of an object is a. velocity. b. acceleration. c. capacity. d. flow.
Tomtit [17]
The term is acceleration.

(b).
6 0
3 years ago
A potter’s wheel of radius 17 cm starts from rest and rotates with constant angular acceleration until at the end of 32 s it is
dedylja [7]

Answer:

α=0.625rad/s^2

v=340m/s

w=10rad/s

θ=320rad

Explanation:

Constant angular acceleration = ∆w/∆t

angular acceleration = 20/32

α=0.625rad/s^2

Linear velocity v=wr

v = 20×17= 340m/s

Average angular velocity

w0+w1/2

w= 0+20/2

w= 20/2

w=10rad/s

What angle did it rotate with

θ=wt

θ= 10×32

=320rad

4 0
3 years ago
A man has a weight of 100 Newtons. How much work is done if he climbs 4meters up a ladder?
Aliun [14]

Answer:

400 J

Explanation:

Work is done when a force that is applied to an object moves that object.

The work is calculated by multiplying the force by the amount of movement of an object

W = F * d

here the man has to work against the gravitational field. (against his weight)

F =100 N

Work done =  F * d

                   =   100 * 4

                   = 400 J

7 0
4 years ago
A man is standing on the edge of a 20.0 m high cliff. He throws a rock horizontally with an initial velocity of 10.0 m/s.
kherson [118]

Answer:

<em>a. The rock takes 2.02 seconds to hit the ground</em>

<em>b. The rock lands at 20,2 m from the base of the cliff</em>

Explanation:

Horizontal motion occurs when an object is thrown horizontally with an initial speed v from a height h above the ground. When it happens, the object moves through a curved path determined by gravity until it hits the ground.

The time taken by the object to hit the ground is calculated by:

\displaystyle t=\sqrt{\frac{2h}{g}}

The range is defined as the maximum horizontal distance traveled by the object and it can be calculated as follows:

\displaystyle d=v.t

The man is standing on the edge of the h=20 m cliff and throws a rock with a horizontal speed of v=10 m/s.

a,

The time taken by the rock to reach the ground is:

\displaystyle t=\sqrt{\frac{2*20}{9.8}}

\displaystyle t=\sqrt{4.0816}

t = 2.02 s

The rock takes 2.02 seconds to hit the ground

b.

The range is calculated now:

\displaystyle d=10\cdot 2.02

d = 20.2 m

The rock lands at 20,2 m from the base of the cliff

5 0
3 years ago
In a maneuver, the jet comes in for a landing on solid ground with a speed of 115 m/s, and its acceleration can have a maximum m
V125BC [204]

Answer:

17.1130952381 s

No

Explanation:

t = Time taken

u = Initial velocity = 115 m/s

v = Final velocity = 0

s = Displacement

a = Acceleration = -6.72 m/s² (negative as it is decelerating)

From the equations of motion

v=u+at\\\Rightarrow t=\dfrac{v-u}{a}\\\Rightarrow t=\dfrac{0-115}{-6.72}\\\Rightarrow t=17.1130952381\ s

The minimum time required to stop is 17.1130952381 s

v^2-u^2=2as\\\Rightarrow s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{0^2-115^2}{2\times -6.72}\\\Rightarrow s=984.00297619\ m

The distance that is required for the jet to stop is 0.98400297619 km which is greater than 0.8 km. So, the jet cannot land on a small tropical island airport.

4 0
3 years ago
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