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ivanzaharov [21]
3 years ago
14

A man has a weight of 100 Newtons. How much work is done if he climbs 4meters up a ladder?

Physics
1 answer:
Aliun [14]3 years ago
7 0

Answer:

400 J

Explanation:

Work is done when a force that is applied to an object moves that object.

The work is calculated by multiplying the force by the amount of movement of an object

W = F * d

here the man has to work against the gravitational field. (against his weight)

F =100 N

Work done =  F * d

                   =   100 * 4

                   = 400 J

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It takes 160 kj of work to accelerate a car from 24.0 m/s to 27.5 m/s. what is the car's mass?
ankoles [38]
Work-Energy :W = 1/2 m ( Vf^2 -Vo^2 )
Vo = 24.0 m/s Initial speed 
 Vf = 27.5 m/s  Final speed 

W = 1/2 m ( Vf^2 -Vo^2 )
160 kj = 1/ 2 m ( 27.5^2  -24.0 ^2)
160kj =  4680 x m
convert kilo joules to jeoules                     160000 j = 4689 xm
m = 160000 j/4689
m = 34.18 kg
4 0
4 years ago
Suppose you wanted to hold up an electron against the force of gravity by the attraction of a fixed proton some distance above i
SCORPION-xisa [38]

Answer:

The value is  r =  5.077 \  m

Explanation:

From the question we are told that

   The  Coulomb constant is  k =  9.0 *10^{9} \  N\cdot  m^2  /C^2

   The  charge on the electron/proton  is  e =  1.6*10^{-19} \  C

    The  mass of proton m_{proton} =  1.67*10^{-27} \  kg

    The  mass of  electron is  m_{electron } =  9.11 *10^{-31} \ kg

Generally for the electron to be held up by the force gravity

   Then    

       Electric force on the electron  =  The  gravitational Force

i.e  

            m_{electron} *  g  = \frac{ k *  e^2  }{r^2 }

         \frac{9*10^9 *  (1.60 *10^{-19})^2  }{r^2 }  =     9.11 *10^{-31 }  *  9.81

         r =  \sqrt{25.78}

         r =  5.077  \  m

7 0
3 years ago
You have a string with a mass of 0.0127 kg. You stretch the string with a force of 9.33 N, giving it a length of 1.93 m. Then, y
melomori [17]

Answer:

wavelength = 0.968 m

frequency = 39.02 Hz

Explanation:

given data

mass = 0.0127 kg

force = 9.33 N

length = 1.93 m

to find out

wavelength and Frequency

solution

we know here linear density that is

linear density = \frac{mass}{length}   .........1

linear density = \frac{0.0127}{1.93}

linear density = 6.5803 × 10^{-3} kg/m

so

wavelength will be here

wavelength = \frac{2L}{n}   ..............2

here n = 4 for forth harmonic

wavelength = \frac{2*1.93}{4}

wavelength = 0.968 m

and

frequency will be for 4th normal mode of vibration is

frequency = \frac{4}{2L} \sqrt{\frac{tension}{linear\ density} }    ..........3

frequency = \frac{4}{2*1.93} \sqrt{\frac{9.33}{6.5803*10^{-3}} }

frequency = 1.036269 × 37.654594

frequency = 39.02 Hz

5 0
3 years ago
A sample of ore containing radioactive strontium 38Sr90 has an activity of 8.2 × 105 Bq. The atomic mass of strontium is 89.908
ahrayia [7]

From the activity values and the decay constant, the mass of of Strontium in the sample is:

1.62 × 10^{-7}g

<h3>What is the decay constant of an element?</h3>

The decay constant of an element is the probability of decay of a nucleus per unit time.

{λ = ln 2 / t1/2 

where;

t1/2 is the half-life of the isotope.

The half-life is converted to seconds since the decay constant is asked in per seconds.

28.8 years = 28.8 × 3.156 × 10^{7} = 908928000 s \\

Hence;

λ = \frac{ln2}{90892800s} = 7.626 s^{-1}

                                       

The activity of the element, A, the decay constant, λ and the number of nuclei, N are related as follows:

  • A = (–) λN

N = \frac{8.25 ×10^{5}}{7.626×10^{-10}} = 1.082 × 10^{15}              

Molar mass of Strontium-90 is 90 g.

1 mole of Strontium-90 contains 6.02×10^23 nuclei.

The mass, m of Strontium in the sample is calculated:

m = 1.082 × 10^{15} × \frac{90 g}{6.02 × 10^{23}} = 1.62 × 10^{-7}g \\

Therefore, the mass of of Strontium in the sample is:

1.62 × 10^{-7} \: g

Learn more about decay constant at: brainly.com/question/17159453

5 0
2 years ago
What exercise will strengthen your legs?
Olin [163]

Answer: Squats and leg lifts

Explanation:

They strengthen your legs!

7 0
3 years ago
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