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3 years ago

What does it mean if the moon is waxing and waning

1 answer:

6 0

Both verbs come from Olde English.
That's why everybody clearly understood their meaning until
a hundred years ago, but nobody understands them now.

"Waxing" = growing

For two weeks after the New Moon, it's growing toward Full.
First it's a waxing crescent for a week, then it's waxing gibbous.

"Waning" = shrinking

For two weeks after the Full Moon, it's shrinking toward New.
First it's waning gibbous for a week, then it's a waning crescent.

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Which type of heating system is often used to heat many buildings from a central location

MakcuM [25]

Central heating is often used in cold climates to heat private houses and public buildings. Such a system contains boiler, furnace, heat pump to heat water, steam or air, all in a central location such as furnace room in a home or a mechanical room in a large building. The use of water as the heat transfer medium is known as hydronics.

3 0

3 years ago

The importance of the Miller–Urey experiment is that (a) it proved beyond doubt that life could have arisen naturally on the you

Blababa [14]

Answer:

Explanation:

5 0

3 years ago

The second-order bright fringe in a single-slit diffraction pattern is 1.35 mm from the center of the central maximum. The scree

Dafna11 [192]

Answer:

The wavelength is 754.2 nm.

Explanation:

Given that,

Diffraction pattern y= 1.35 mm

Width = 0.838 mm

Distance D= 75 cm

We need to calculate the wavelength

Using formula of diffraction pattern

$y=\dfrac{m\lambda D}{d}$

$\lambda=\dfrac{yd}{mD}$

Where, y = diffraction pattern

m = order

d = width

D = distance

Put the value into the formula

$\lambda=\dfrac{1.35\times10^{-3}\times0.838\times10^{-3}}{2\times75\times10^{-2}}$

$\lambda=7.542\times10^{-7}\ m$

$\lambda=754.2\ nm$

Hence, The wavelength is 754.2 nm.

4 0

3 years ago

Step by step process on how to solve this problem

rusak2 [61]

Step-1: Remember or look up the formula for the force of gravity between two objects. F = G · m₁ · m₂ / R²

Step-2: Remember or look up the value of G. G = 6.67 x 10⁻¹¹ m³·kg/s²

Step-3: Write the numbers you know into the formula.

(1.989 x 10²⁰ Newtons) =

(6.67 x 10⁻¹¹ mtr³·kg/s²) · (5.9742 x 10²⁴ kg) · (moon mass) / (3.84 x 10⁸ mtr)²

Step-4: Sit back, relax, take your time, look this mess over, carefully, end-to-end, and decide how to solve it for (moon mass) .

Step-5: Divide each side by (6.67x10⁻¹¹mtr³·kg/s²)·(5.9742x10²⁴kg)/(3.84x10⁸mtr)²:

Moon mass =

(1.989x10²⁰ Newtons)·(3.84x10⁸ mtr)²/(6.67x10⁻¹¹ mtr³·kg/s²)·(5.9742x10²⁴ kg)

Step-6: Crunch the numbers. Be careful to KEEP all the units as you go along. When you're done, the units of your answer will be the first instant indication if you made a mistake. You're looking for the MASS of the moon. If the answer doesn't have units of 'kg', then that'll be an immediate red flag, telling you that there's been a mistake somewhere.

Moon mass =

(1.989x10²⁰ Newtons)·(3.84x10⁸ mtr)²/(6.67x10⁻¹¹ mtr³·kg/s²)·(5.9742x10²⁴ kg)

Collect the numbers, and collect the units:

Moon mass = (1.989x10²⁰ · (3.84x10⁸)² / (6.67x10⁻¹¹ · 5.9742x10²⁴)

(kg-mtr/s² · mtr²)/(mtr³·kg/s² · kg)

Moon mass = (1.989 · 3.84² x 10³⁶) / (6.67 · 5.9742 x 10¹³)

(kg-mtr/s² · mtr²)/(mtr³·kg/s² · kg)

Moon mass = 0.736 x 10²³ kg

Moon mass = 7.36 x 10²² kg

Step 7: Look it up in a book or online. See if you're anywhere close.

When I search "moon mass" on Floogle, the first hit says

" 7.348 x 10²² kg " .

yay ! I'm satisfied.

6 0

3 years ago

A car of mass 775 kg traveling at a velocity of 30 m/s in the positive x-direction crashes into the rear of a truck of mass 1,47

Thepotemich [5.8K]

Answer:

velocity of the car is 7.3516 m/s

Explanation:

M1v1a + m2v1b = m1v2a + m2v2b

775*30 + 1475*0 = 775*v2a+1475*11.9

Let v2a be x

23250 + 0 = 775x + 17552.5

775x = 23250-17552.5

775x = 5697.5

X = 7.3516 m/s

4 0

3 years ago