If the acceleration is positive, what does that mean about the object’s velocity? What about if it was negative?
2 answers:
Answer:
Positive Velocity and Negative Acceleration
Observe that the object below moves in the positive direction with a changing velocity. An object which moves in the positive direction has a positive velocity. If the object is slowing down then its acceleration vector is directed in the opposite direction as its motion (in this case, a negative acceleration). The dot diagram shows that each consecutive dot is not the same distance apart (i.e., a changing velocity). The position-time graph shows that the slope is changing (meaning a changing velocity) and positive (meaning a positive velocity). The velocity-time graph shows a line with a negative (downward) slope (meaning that there is a negative acceleration); the line is located in the positive region of the graph (corresponding to a positive velocity). The acceleration-time graph shows a horizontal line in the negative region of the graph (meaning a negative acceleration).
Explanation:
In the image down below
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Answer:
The speed is 42210 m/s.
Explanation:
Given that,
Normally wavelength
Observed spectral line
We need to calculate the change in wavelength
Using formula of wavelength
We need to calculate the value of z
Using formula for z
Put the value into the formula
We need to calculate the speed
Using formula of speed
Put the value into the formula
Hence, The speed is 42210 m/s.
Answer: (a) The work done by this force on the particle is 42.71 J.
(b) The change in the potential energy of the system is -42.71 J.
(c) The kinetic energy the particle is 62.96 J.
Explanation:
(a) For the given situation, expression for work done is as follows.
W =
=
=
=
=
= 26.52 + 20.6 - 0.81 - 3.6
= 42.71 J
Hence, the work done by this force on the particle is 42.71 J.
(b) Expression for a conservative force is as follows.
F =
dU = -Fdx
=
= -42.71 J
Therefore, the change in the potential energy of the system is -42.71 J.
(c) According to the work energy theorem,
W =
= W
=
where, u = velocity of the mass at x = 0.9 m
u = 3.0 m/s, m = 4.50 kg
As,
=
= 62.96 J
Therefore, the kinetic energy the particle is 62.96 J.