Answer:
The fraction of kinetic energy to the total energy is 
.
Explanation:
displacement is one third of the amplitude.
Let the amplitude is A.
x= A/3
The kinetic energy of the body executing SHM is
The total energy is
Divide (1) by (2)
There are two main types of friction, static friction and kinetic friction. Static friction operates between
It would be A they model all of earths surfaces because that’s why it was made it was to show the world in a smaller form.
Answer:
2. Same force; same impulse; Mini Cooper has greater change in velocity
4. Same momentum
6. It is distributed to the two halves
Explanation:
I will do the even problems as examples.
2. From Newton's third law, we know the bulldozer and Mini Cooper will experience equal but opposite forces. So the magnitude of the force is the same.
Impulse is force times time. Since the force is the same, and the amount of time is the same, then the impulse is the same.
Impulse is equal to change in momentum, or mass times change in velocity. Since the Mini Cooper has the smaller mass, it has the greater change in velocity.
4. Momentum is mass times velocity. The weight of the rover is different on Mars than on Earth, but the mass is still the same. Therefore, if the rover moves at the same speed, it will have the same momentum.
6. The pencil's momentum is conserved. When the pencil breaks in half, half the momentum goes to one half of the pencil, and half the momentum goes to the other half of the pencil.
There are two units of sound: intensity and in decibels. Decibels are not additive, you must convert it first to units of intensity (W/m²) using this formula:
dB = 10 log(I/10⁻¹²)
A. 100 dB = 10 log(I/10⁻¹²)
Solving for I,
I = 0.01 W/m²
90 dB = 10 log(I/10⁻¹²)
Solving for I,
I = 0.001
Ratio = 0.01/0.001 = 10
<em>Thus,the choir is 10 times more intense than the soloist.</em>
B. Since there are 90 singers, there would be 9 groups of 10-person choir that produces 100 dB or 0.01 W/m². The total intensity would be
Total intensity = 0.01 W/m² (original choir) + 0.001 W/m² (soloist) + 10(0.01 W/m²) (additional 90 singers) = 0.111 W/m²
dB = 10 log(0.111/10⁻¹²) = <em>110.45 dB</em>
C. Rock concert:
120 dB = 10 log(I/10⁻¹²)
Solving for I,
I = 1 W/m²
Ratio = 1/0.111 = 9
<em>Therefore, the rock concert is 9 times more intense than the choir concert.</em>
