How does soil, trees, and air might result in a tradeoff

The energy of a wave will remain constant if which of the following changes are made to it?AThe wavelength is cut in half, and t

Makovka662 [10]

The energy of a wave will remain constant if which of the following changes are made to it is given below

Explanation:

1.In electromagnetic waves, energy is transferred through vibrations of electric and magnetic fields. In sound waves, energy is transferred through vibration of air particles or particles of a solid through which the sound travels. In water waves, energy is transferred through the vibration of the water particles.

2.First of all for light which is a electromagnetic wave c=frequency*wavelength. As the wavelength increases the frequency decreases. This can be physically understood as the increase in red shift of the light. Also energy =h*frequency,hence increasing wavelength decreases the energy carried by the photon.

3.Wave frequency is related to wave energy. the more energy in a wave, the higher its frequency. The lower the frequency is, the less energy in the wave.

4 0

3 years ago

A stone is thrown into a well and the splash is heard after 3s. (speed of sound : 340m/s) . 1.) What time did the stone take to

miss Akunina [59]

1.)3s
2.)6s
3.)1020m

hope this help

8 0

3 years ago

How to solve 2.14 using calculus

trasher [3.6K]

Answer:

The acceleration is $6.42\frac{m}{s^2}$

Explanation:

Given the velocity function:

$v=0.86\frac{m}{s^3}t^2$

you can obtain the instantaneous acceleration "a" as its first derivative:

$a=\dot{v}=2\cdot0.86\frac{m}{s^3}\cdot t=1.72\frac{m}{s^3}t$

To determine the value of "a" when the velocity was 12m/s, you need to figure out the value for "t" when this happens. At what time t is the velocity 12m/s?

$12.0\frac{m}{s}=0.86\frac{m}{s^3}t^2\implies t=3.74s$

This value of t is less than the 5 seconds mentioned in the text - so that is a good sign that the formula is valid for this value. And so you can use t=3.47s in the derivative (acceleration) above:

$a=1.72t=1.72\frac{m}{s^3}\cdot 3.74s = 6.42\frac{m}{s^2}$

3 0

3 years ago

a) Calculate the height (in m) of a cliff if it takes 2.21 s for a rock to hit the ground when it is thrown straight up from the

DedPeter [7]

Answer:

a)Height of the cliff = 6.19 m

b) t = 0.571 s

Explanation:

We need to first calculate the time it takes the rock to go up and come down to the cliff's level first.

Using the equations of motion,

g = -9.8 m/s², u₁ = Initial velocity = 8.03 m/s,

v = velocity at maximum height = 0 m/s

t₁ = time to reach maximum height = ?

a) v₁ = u₁ + gt₁

0 = 8.03 - 9.8t

t₁ = 8.03/9.8 = 0.819 s

Total time of flight for the rock to leave the cliff and reach maximum height = 0.819 s

Height that the rock attains, measured from the top of the cliff to the maximum height, y₁ = ?

y₁ = ut₁ + gt₁²/2 = 8.03(0.819) - 9.8(0.819²)/2 = 3.29m

Total time of flight of the rock, t = t₁ + t₂

Subtracting the time obtained from the first part (0.819 s) from the total time would give the time it took the rock to travel from maximum height reached to the ground.

t₂ = 2.21 - 0.819 = 1.391 s

Let y = total height fallen through = y₁ + (height of the cliff) = y₁ + H = ?

g = 9.8 m/s²

t₂ = 1.391 s

u₂ = initial velocity for 2nd phase of rock motion = velocity at maximum height = 0 m/s

y = u₂t₂ + gt₂²/2

y = 0 + 9.8(1.391²)/2

y = 9.48 m

y = y₁ + H

9.48 = 3.29 + H

H = 9.48 - 3.29 = 6.19 m

b) y = H = 6.19 m, u = 8.03 m/s, t = ?,

y = ut + gt²/2

6.19 = 8.03t + 9.8t²/2

4.9t² + 8.03t - 6.19 = 0

Solving the quadratic eqn

t = -2.21 s or 0.571 s

Since time can only be positive,

t = 0.571 s

(PROVED)

4 0

3 years ago

Read 2 more answers

What type of force cause an object to accelerate??

Olin [163]

ANY force causes an object to accelerate, just as long as there are not
some other forces on the object that cancel out the first one.

Are you looking for the answer ... an "UNBALANCED" force ?
That's a very poor way to describe it, because there's no such thing
as a balanced or unbalanced force. The thing that's balanced or
unbalanced is a GROUP of forces, not a single force.

8 0

3 years ago