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ehidna [41]
4 years ago
7

A boy is pushing on a heavy door, trying to slide it open. His friend stands behind him and helps him push.

Chemistry
2 answers:
GrogVix [38]4 years ago
7 0
Ohh love chemistry okay had this in my test its A-<span>The net force applied will increase</span>
7nadin3 [17]4 years ago
3 0
"<span>A. The net force applied will increase." This is because there is more force being applied. </span>
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"Why does a hamburger have fewer calories than a steak? Because it's in the ground state!" Explain the joke while also highlight
jekas [21]

Answer:

it means a hamburger has less calories bc its referring to steak that has been grounded and the highlight would be calories

5 0
3 years ago
A 5.325g sample of methyl benzoate, a compound in perfumes , was found to contain 3.758 g of carbon, 0.316 g of hydrogen, and 1.
Alexxandr [17]

<u>Answer:</u> The empirical and molecular formula of the compound is C_4H_4O and C_8H_8O_2 respectively

<u>Explanation:</u>

We are given:

Mass of C = 3.758 g

Mass of H = 0.316 g

Mass of O = 1.251 g

To formulate the empirical formula, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{3.758g}{12g/mole}=0.313moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.316g}{1g/mole}=0.316moles

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{1.251g}{16g/mole}=0.078moles

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.078 moles.

For Carbon = \frac{0.313}{0.078}=4.01\approx 4

For Hydrogen  = \frac{0.316}{0.078}=4.05\approx 4

For Oxygen  = \frac{0.078}{0.078}=1

  • <u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : H : O = 4 : 4 : 1

The empirical formula for the given compound is C_4H_4O

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is:

n=\frac{\text{Molecular mass}}{\text{Empirical mass}}

We are given:

Mass of molecular formula = 130 g/mol

Mass of empirical formula = 68 g/mol

Putting values in above equation, we get:

n=\frac{130g/mol}{68g/mol}=1.9\approx 2

Multiplying this valency by the subscript of every element of empirical formula, we get:

C_{(2\times 4)}H_{(2\times 4)}O_{(2\times 2)}=C_8H_8O_2

Hence, the empirical and molecular formula of the compound is C_4H_4O and C_8H_8O_2 respectively

4 0
3 years ago
At a certain temperature this reaction follows first-order Kinetics with a rate constant of 0.0660
Juli2301 [7.4K]

Answer:

After 26.0s, the concentration of HI decreases from 0.310M to 0.0558M.

Explanation:

Based on the reaction of the problem, you have as general kinetic law for a first-order reaction:

ln[HI] = -kt + ln [HI]₀

<em>Where [HI] is actual concentration after time t, </em>

<em>k is rate constant </em>

<em>and [HI]₀ is initial concentration of the reactant. </em>

Initial concentration of HI is 0.310M,

K is 0.0660s⁻¹,

And the actual concentration is 0.0558M:

ln[HI] = -kt + ln [HI]₀

ln[0.0558M] = -0.0660s⁻¹*t + ln [ 0.310M]

-1.7148 = -0.0660s⁻¹*t

26.0s = t

<h3>After 26.0s, the concentration of HI decreases from 0.310M to 0.0558M</h3>

<em />

3 0
3 years ago
Which of the following is considered a major process flow structure?
qaws [65]
Since lead time is the time period between <span>the starting and completion of producing a product, lead time is a major process flow structure.</span>
3 0
3 years ago
3.8x10^-4 g is dissolved into 450g of water . Find the concentration in ppm
IrinaK [193]

Answer:

0.84ppm

Explanation:

  Mass of solute  = 3.8 x 10⁻⁴g

  Mass of solution  = 450g

Unknown is the concentration in ppm; parts per million

The parts per million is one of the units of representing small concentration of solutes in a solution.

Solutes are the substances dissolving in another to give solution.

Here the concentration is expressed in a million units.

Concentration in ppm  = \frac{mass of solute}{mass of solution}  x 10⁶

                                     = \frac{3.8 x 10^{-4} }{450}   x 10⁶

                                     = 0.84ppm

4 0
3 years ago
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