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sweet [91]
3 years ago
11

Using the spectra data below, which structure best matches this data? c4h8o 1h nmr triplet at 1.05 ppm (3h) singlet at 2.13 ppm

(3h) quartet at 2.47 ppm (2h) ir spectrum: there is a strong peak near 1700 cm-1.

Chemistry
1 answer:
Delicious77 [7]3 years ago
5 0

Answer:

Butan-2-one

Explanation:

1. 1700 cm⁻¹

A strong peak near 1700 cm⁻¹ is almost certainly a carbonyl (C=O) group.

2. Triplet-quartet

A triplet-quartet pattern indicates an ethyl group.

The 2H quartet is a CH₂ adjacent to a CH₃. The peak normally occurs at δ 1.3, but it is shifted 1.2 ppm downfield to δ 2.47 by an adjacent C=O group.

The 3H triplet at δ 1.05 is the methyl group. It, too, is shifted downfield from its normal position at δ 0.9. The effect is smaller, because the methyl group is further from the carbonyl.

3. 3H(s) at δ 2.13

This indicates a CH₃ group with no adjacent hydrogen atoms.

It is shifted 0.8 ppm downfield to δ 2.13 by the adjacent C=O group.

4. Identification

The identified pieces are CH₃CH₂-, -(CO)-, and -CH₃. There is only one way to put them together: CH₃CH₂-(C=O)-CH₃.

The compound is butan-2-one.

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Answer:

86.5%

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

2Na + 2HF –> 2NaF + H2

Next, we shall determine the theoretical yield of the hydrogen gas, H2. This is illustrated:

From the balanced equation above,

2 moles of Na reacted to produce 1 mole of H2.

Therefore, 5.75 moles of Na will react to produce = (5.75 x 1)/2 = 2.88 moles of H2.

Therefore, the theoretical yield of Hydrogen gas, H2 is 2.88 moles.

Finally, we shall determine the percentage yield of Hydrogen gas, H2. This can be obtained as follow:

Actual yield of H2 = 2.49 moes

Theoretical yield of H2 = 2.88 moles

Percentage yield of H2 =.?

Percentage yield = Actual yield /Theoretical yield x 100

Percentage yield = 2.49/2.88 x 100

Percentage yield = 86.5%

Therefore, the percentage yield of Hydrogen gas, H2 is 86.5%.

6 0
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3 0
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Answer:

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Explanation:

Hello!

In this case, since the Dalton's law help us to realize that the total pressure of a gas mixture is computed by adding the partial pressure of each composing gas, for the mixture formed by carbon dioxide, oxygen sulfide (should be hydrogen sulfide instead) and air, we can write:

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Thus, given the total pressure and the partial pressures of both carbon dioxide and hydrogen sulfide, the partial pressure of the remaining air would be:

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Best regards!

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