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sweet [91]
3 years ago
11

Using the spectra data below, which structure best matches this data? c4h8o 1h nmr triplet at 1.05 ppm (3h) singlet at 2.13 ppm

(3h) quartet at 2.47 ppm (2h) ir spectrum: there is a strong peak near 1700 cm-1.

Chemistry
1 answer:
Delicious77 [7]3 years ago
5 0

Answer:

Butan-2-one

Explanation:

1. 1700 cm⁻¹

A strong peak near 1700 cm⁻¹ is almost certainly a carbonyl (C=O) group.

2. Triplet-quartet

A triplet-quartet pattern indicates an ethyl group.

The 2H quartet is a CH₂ adjacent to a CH₃. The peak normally occurs at δ 1.3, but it is shifted 1.2 ppm downfield to δ 2.47 by an adjacent C=O group.

The 3H triplet at δ 1.05 is the methyl group. It, too, is shifted downfield from its normal position at δ 0.9. The effect is smaller, because the methyl group is further from the carbonyl.

3. 3H(s) at δ 2.13

This indicates a CH₃ group with no adjacent hydrogen atoms.

It is shifted 0.8 ppm downfield to δ 2.13 by the adjacent C=O group.

4. Identification

The identified pieces are CH₃CH₂-, -(CO)-, and -CH₃. There is only one way to put them together: CH₃CH₂-(C=O)-CH₃.

The compound is butan-2-one.

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Brrunno [24]

Answer:

ΔT = 0.78 °C

Explanation:

Given data:

Mass of Al = 9.5 g

Specific heat capacity of Al = 0.9 J/g.°C

Temperature change = ?

Heat added = 67 J

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

67 J = 9.5 g × 0.9 j/g.°C × ΔT

67 J = 85.5 j/°C × ΔT

ΔT = 67 J  /  85.5 j/°C

ΔT = 0.78 °C

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3 years ago
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C.

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What happens to the number of waves when you decrease the wavelength?
Keith_Richards [23]

C

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6 0
3 years ago
A 0.1375-g sample of solid magnesium is burned in a constant-volume bomb calorimeter that has a heat capacity of 3024 J/°C. The
Anna35 [415]

Answer:

-24.76 kJ/g; -601.8 kJ/mol

Explanation:

There are two heat flows in this experiment.

Heat from reaction + heat absorbed by calorimeter = 0

             q1                +                     q2                         = 0

           mΔH             +                    CΔT                        = 0

Data:

m = 0.1375 g

C = 3024 J/°C

ΔT = 1.126 °C

Calculations:

0.1375ΔH + 3024 × 1.126 = 0

           0.1375ΔH + 3405 = 0

                        0.1375ΔH = -3405

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ΔH = -24.76 kJ/g ×24.30 g/mol = -601.8 kJ/mol

3 0
3 years ago
A cylinder rod formed from silicon is 21.3 cm long and has a mass of 5.00 kg. The density of silicon is 2.33 g/cm3. What is the
Vinil7 [7]

Answer:

11.32cm

Explanation:

This question describes a cylinder rod formed from silicon with length 21.3cm and mass 5kg. The density of the silicon is 2.33g/cm3.

To calculate the diameter, the radius is needed. To calculate the radius, the volume is needed. To calculate the volume, the formula: density = mass (m) / volume (V) is used.

Mass = 5kg, which is 5 kg × 1000g = 5000g

Density= 2.33g/cm3

Hence; volume= mass / density

= 5000/2.33

= 2145.9 cm3

Volume of cylinder= πr^2h

Where h= 21.3cm and π= 3.142

That is; r^2 = volume/πh

= r^2 = 2145.9/3.142×21.3

= r^2 = 2145.9/66.9246

= r^2 = 32.06

r= √32.06

r= 5.66cm

If radius of the cylinder is 5.66cm, the diameter is twice of the radius.

That is, diameter (d) = 5.66 × 2

= 11.32 cm

Therefore, the diameter of the cylinder is 11.32cm.

6 0
3 years ago
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