Where does secretion occur in the nephron?

Elena-2011 [213]

Prepare a 1% copper sulfate solution. To make this solution, weigh 1 gram of copper sulfate (CuSO4 ·5H2O), dissolve in a small amount of distilled water in a 100 ml volumetric flask and bring to volume. Label this as 1% copper sulfate solution.

4 0

3 years ago

At its critical point, ammonia has a density of 0.235 g cm23. You have a special thickwalled glass tube that has a 10.0mm outs

salantis [7]

Answer:

$\large \boxed{\text{69.3 mg}}$

Explanation:

1. Volume of sealed tube

Assume the sealed tube is a right circular cylinder in which the cap and the base are also 4.20 mm thick.

Its outside dimensions are 155 mm long × 10.0 mm diameter.

Its inside dimensions are

h = 155 mm - 2 × 4.20 mm = 146.6 mm

r = 5.0 mm - 4.20 mm = 0.8 mm

V = πr²h = π(0.8)²× 146.6 mm³ = 294.8 mm³ = 0.2948 cm³

2. Calculate the mass of NH₃

$\begin{array}{rcl}\text{Density} & = & \dfrac{\text{Mass}}{\text{Volume}}\\\\\rho & = &\dfrac{m}{V}\\\\0.235 \text{ g$\cdot$ cm}^{-3} & = & \dfrac{m}{\text{0.2948 cm}^{3}}\\\\m & = & \text{0.0693 g}\\& = & \textbf{69.3 mg}\\\end{array}\\\text{You must seal $\large \boxed{\textbf{69.3 mg}}$ of ammonia in the tube.}$

4 0

3 years ago

Which of the following affects cell potential?

Slav-nsk [51]

Answer:

the standard cell potential value

Explanation:

For every cell, we can calculate its standard electrode potential from the table of standard electrode potentials listed in many textbooks.

However, from Nernst's equation;

Ecell= E°cell - 0.0592/n log Q

Hence the standard cell potential (E°cell) affects the value of the calculated cell potential Ecell from Nernst's equation as stated above.

3 0

3 years ago

What fundamental building block makes up all matter in the universe

Sloan [31]

The building block that makes up all matter in the universe is atoms.

Hope that helps you:)

6 0

3 years ago

Which of the following steps correctly describes the preparation of 0.5 M solution of FeCl3?

Marizza181 [45]

Answer:

Option A is correct

Explanation:

Data given:

Steps for preparation of 0.5 M solution = ?

Solution:

Molarity: This the term used for the concentration of the solution. It is the amount of solute in moles dissolve in 1 Liter of solution.

Formula used for Molarity

Molarity = number of moles of solute / 1 L of solution

From the above definition and formula it is clear that we have to know the following things.

no. of moles of f the solute

we also should know that of what concentration we are preparing solution in terms of molarity
The total amount of should be in liter of solution not solvent separately

Now:

As we couldn't weight mole on balance so have to convert moles to grams by using molar mass or mass in grams formula

As

1 mole = mass in grams / molar mass

so to convert mole to mass rearrange the above equation

mass in grams = 1 mole x molar mass

So,

1 mole of any substance equal to its molar mass

Now, to prepare 0.5 M solution of FeCl₃

First we find molar mass and weigh it

So,

1 mole of FeCl₃ = molar mass of FeCl₃

for 0.5 M

Multiply the molar mass with 0.5

To make 1 L of solution

As we know that molarity is the amount of solution in liter of solution not solvent, so we add the calculated amount of solute in volumetric flask and then add water till the 1 L mark. that is amount of solute plus solvent combined form 1 L of Solution.

So, Option A is correct: Find the molar mass of FeCl3 and multiply by 0.5 to find the amount. Add this amount in a volumetric flask and add water till the 1 L mark

3 0

3 years ago