Answer:
Adding sodium or potassium hydroxide in amounts sufficient to convert all the H2SO4 into Na2SO4 would approximately neutralize the solution. The error would be the result of the imbalance between the basicity of the hydroxide and the acidity of the bisulfate (HSO4) anion. An adjustment in concentration would have to be made to achieve an accurate approximate pH of 7. But then you didn’t ask how much we would need to add.
Explanation:
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<h3>
Answer:</h3>
43.27 g Mg
<h3>
Explanation:</h3>
The balanced equation for the reaction between magnesium metal and hydrochloric acid is;
Mg(s) + 2HCl(aq) → MgCl₂(aq) + H₂(g)
From the equation;
1 mole of magnesium reacts with 2 moles of HCl
We are given;
3.56 moles of Mg and 3.56 moles of HCl
Using the mole ratio;
3.56 moles of Mg would react with 7.12 moles of HCl, and
3.56 moles of HCl would react with 1.78 moles of Mg
Therefore;
The amount of magnesium was in excess;
Moles of Mg left = 3.56 moles - 1.78 moles
= 1.78 moles
But; 1 mole of Mg = 24.305 g/mol
Therefore;
Mass of magnesium left = 1.78 moles × 24.305 g/mol
= 43.2629 g
= 43.27 g
Thus, the mass of magnesium that remained after the reaction is 43.27 g
Answer is: total pressure of the system is 2.4 atm.
Boyle's Law (the pressure volume law): volume of a given amount of gas held varies inversely with the applied pressure when the temperature and mass are constant.
p₁V₁ = p₂V₂ (the product of the initial volume and pressure is equal to the product of the volume and pressure after a change).
1.2 atm · 2 L = p₂ · 1 L.
p₂ = 1.2 atm · 2 L / 1 L.
p₂ = 2.4 atm.
When pressure goes up, volume goes down.
When volume goes up, pressure goes down.
The unbalanced Equation is
electricity
KI (aq) + H2O (l) -------------> H2 (g) + I2(g) + KOH(aq)
Answer:
34.2 g is the mass of carbon dioxide gas one have in the container.
Explanation:
Moles of 
:-
Mass = 49.8 g
Molar mass of oxygen gas = 32 g/mol
The formula for the calculation of moles is shown below:
Thus,
Since pressure and volume are constant, we can use the Avogadro's law as:-
Given ,
V₂ is twice the volume of V₁
V₂ = 2V₁
n₁ = ?
n₂ = 1.55625 mol
Using above equation as:
n₁ = 0.778125 moles
Moles of carbon dioxide = 0.778125 moles
Molar mass of 
= 44.0 g/mol
Mass of = Moles × Molar mass = 0.778125 × 44.0 g = 34.2 g
<u>34.2 g is the mass of carbon dioxide gas one have in the container.</u>
