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nirvana33 [79]
3 years ago
12

If a sulfur ion with 16 protons and 17 electrons loses one electron, what is the resulting charge?

Chemistry
1 answer:
Rzqust [24]3 years ago
4 0
The result will be no charge or neutral.. Because before losing an electron, the charge on ion was negative but after removal of 1 electron the charge is neutral.
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g What volume (mL) of the partially neutralized stomach acid was neutralized by NaOH during the titration? (portion of 25.00 mL
Pani-rosa [81]

The question is incomplete, here is the complete question:

What volume (mL) of the partially neutralized stomach acid having concentration 2M was neutralized by 0.01 M NaOH during the titration? (portion of 25.00 mL NaOH sample was used; this was the HCl remaining after the antacid tablet did it's job)

<u>Answer:</u> The volume of HCl neutralized is 0.125 mL

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCl (Stomach acid)

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=1\\M_1=2M\\V_1=?mL\\n_2=1\\M_2=0.01M\\V_2=25mL

Putting values in above equation, we get:

1\times 2\times V_1=1\times 0.01\times 25\\\\V_1=\frac{1\times 0.01\times 25}{1\times 2}=0.125mL

Hence, the volume of HCl neutralized is 0.125 mL

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