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Tanzania [10]
3 years ago
15

QUESTION 1 (POLL)

Chemistry
1 answer:
Airida [17]3 years ago
4 0

Answer:

They stay the same

Explanation:

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Determine the mass of 5.2 x 10 power of 21 molecules of propanol C3H7OH(l), on grams.
Alja [10]

n(\text{C}_3\text{H}_7\text{OH}) = N(\text{C}_3\text{H}_7\text{OH}) / N_A\\ \phantom{n(\text{C}_3\text{H}_7\text{OH})} = 5.2 \times 10^{21} / (6.02 \times 10^{23})\\ \phantom{n(\text{C}_3\text{H}_7\text{OH})} = 8.6 \times 10^{-3} \; \text{mol}

where N_A = 6.02 \times 10^{23}\; \text{mol}^{-1} the Avogadro's constant that relates the number of particles to their number, in the unit moles \text{mol}.

The molar mass of propanol- mass per mole propanol- can be directly deduced from its molecular formula with reference to a modern periodic table.

M(\text{C}_3\text{H}_7\text{OH}) = \underbrace{3 \times 12.01}_{\text{carbon}} + \underbrace{8 \times 1.008}_{\text{hydrogen}} + \underbrace{1\times 16.00}_{\text{oxygen}} = 60.09 \; \text{g} \cdot \text{mol}^{-1}

8.6 \times 10^{-3} \; \text{mol} of propanol molecules would thus have a mass of 8.6 \times 10^{-3} \; \text{mol} \times 60.09 \; \text{g} \cdot \text{mol}^{-1} = 0.52 \; \text{g}

5 0
3 years ago
What properties of matter explain why the weight of an object on the moon is different than the weight of the same object on ear
algol13

Answer:

Gravity explains this.

Explanation:

Weights and mass are different terms .

Weight is defined as the force exerting on the surface due to the mass and gravity of acceleration.

W=m*g

Here mass is related to the density of the body. So as the density would be same mass woulnt vary.

Whereas the Gravity changes due to the property of the planet.

Gravity is different for different planets and hence moon and earth have two different values.

So the mass i.e density remains same on both planets but the g value always changes hence weight is different.

4 0
3 years ago
The part of an experiment used to compare all the other groups
Westkost [7]
Control/Control Group
3 0
3 years ago
Suppose that 33.3 J of heat is added to an ideal gas. The gas expands at a constant pressure of 1.45 104 Pa while changing its v
levacccp [35]

Answer:

ΔU = 25.8 J

Explanation:

The gas absorbs 33.3 J of heat, that is, Q = 33.3 J.

The work (W) of expansion can be calculated using the following expression:

W = -P. ΔV

where,

P is the external pressure

ΔV is the change in volume

W = -1.45 × 10⁴ N . m⁻² × (8.40 × 10⁻⁴ m³ - 3.24 × 10⁻⁴ m³) = -7.48 J

The change in the internal energy (ΔU) is:

ΔU = Q + W

ΔU =  33.3 J + (-7.48 J) = 25.8 J

5 0
3 years ago
In your own words, please describe the difference between a complete ionic equation and a net ionic equation.
beks73 [17]

Explanation:

In the molecular equation for a reaction, all of the reactants and products are represented as neutral molecules (even soluble ionic compounds and strong acids). In the complete ionic equation, soluble ionic compounds and strong acids are rewritten as dissociated ions.

The net ionic equation is a chemical equation for a reaction that lists only those species participating in the reaction. The net ionic equation is commonly used in acid-base neutralization reactions, double displacement reactions, and redox reactions.

6 0
3 years ago
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