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klemol [59]
3 years ago
5

If Sarah is 24 years younger than her mother and if the sum of their ages is 68, how old is Sarah?

Mathematics
2 answers:
pav-90 [236]3 years ago
7 0
24 + x = 68 so 68-24=x.
68-24=44
Sarah's mother is 44
mariarad [96]3 years ago
4 0

Answer:

24 + x = 68 so 68-24=x.

68-24=44

Sarah's mother is 46

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60.April would like to invest $200 in the bank for one year. Three banks all have a nominal APR of 1.5%, but compound the intere
mojhsa [17]

Answer:

$203.02

Step-by-step explanation:

Since the bank in question compounds interest continuously, the following equation should be used to determine the final balance (B) in April's account:

B= 200*e^{i*t}

Where "e" is a mathematical constant approximated as 2.7183, "i" is the interest rate (1.5%) and "t" is the investment time in years (1):

B= 200*e^{0.015*1}

B= 203.02

April's balance would be $203.02 after one year.

5 0
3 years ago
Find all points having an x-coordinate of 2 whose distance from the point (-1,-2) is 5
mariarad [96]
The\ equation\ of\ the\ circle:(x-a)^2+(y-b)^2=r^2\\\\where\ (a;\ b)\ -the\ coordinates\ of\ the\ center;\ r-the\ radius\\-----------------------------\\(-1;-2)-the\ center\ of\ the\ circle\\r=5\\\\The\ equation:(x+1)^2+(y+2)^2=5^5\\\\Put\ x=2\ to\ the\ equation:\\\\(2+1)^2+(y+2)^2=25\\3^2+(y+2)^2=25\\9+(y+2)^2=25\\(y+2)^2=25-9\\(y+2)^2=16\iff y+1=\pm\sqrt{16}\\\\y+1=-4\ or\ y+1=4\ \ \ \ \ |subtract\ 1\ from\ both \sides\\y=-5\ or\ y=3\\\\Answer:(2;-5)\ and\ (2;\ 3).
5 0
3 years ago
Two people start from the same point. One walks east at 4 mi/h and the other walks northeast at 8 mi/h. How fast is the distance
kvasek [131]

Answer:

5.89 mi/h

Step-by-step explanation:

This problem can be solved by using different methods. I will use vectors since it's the simplest way in which we can solve it. This can be solved by using related rates of change though.

First, we start by drawing a diagram with the velocity vectors.

A= velocity of the first person

B= velocity of the second person

C= velocity in which they are moving away from each other.

Since there is no acceleration in the problem, we can suppose we are talking about constant speeds, so the velocity at which they are moving away from each other will always remain constant. (It doesn't matter what time it is, the velocity will always be the same)

Having said this we can solve this problem by using the components, by using law of cosines or graphically. I will use law of cosines. The idea is to find the length of side c.

Law of cosines:

C^{2}=A^{2}+B^{2}-2ABcos \gamma

so we can solve the formula for C so we get:

C=\sqrt{A^{2}+B^{2}-2ABcos \gamma}

and now we can substitute the values we know:

C=\sqrt{(4)^{2}+(8)^{2}-2(4)(8)cos 45^{o}}

C=\sqrt{16+64-32\sqrt{2}}

C=\sqrt{80-32\sqrt{2}} mph

if we want an exact answer, then that will be the exact answer, which approximates to:

C=5.89 mph

4 0
3 years ago
Ignore the answers! I need help I’ll mark u brainly
Vinil7 [7]
7. X2=25
X=5, x=—5

8. (X—3)2=49
X=10, x=—4

9. X2+3x—28.
X=4, x=—7.

10. 5x2–8=3x.
X=8/5, x=—1
8 0
3 years ago
Read 2 more answers
What is 2 +4s=16 on a graph
Annette [7]
That is the answer !! hope this helped

4 0
2 years ago
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