Solution :
Cd(s) ----------------------> 
(aq) + 2
, 
= 0.34 v
(aq) + 2 ------------> Cu (s) , = -0.04 v
----------------------------------------------------------------------------------------------
Cd(s) + (aq) -------------> (aq) + Cu (s) , = 0.30 v
The cell potential is defined as the measure of 
between the 
of an electrochemical cell.
Answer:
77 L of water can be made.
Explanation:
Molar mass of 
= 32 g/mol
So, 55 g of = 
mol of = 1.72 mol of
As hydrogen is present in excess amount therefore is the limiting reagent.
According to balanced equation, 1 mol of produces 2 mol of 
.
So, 1.72 mol of produce 
mol of or 3.44 mol of .
Let's assume gas behaves ideally at STP.
Then, 
, where P, V, n, R and T represents pressure, volume, no. of moles, gas constant and temperature in kelvin scale respectively.
At STP, pressure is 1 atm and T is 273 K.
Here, 
= 3.44 mol and R = 0.0821 L.atm/(mol.K)
So, 
Option (b) is correct.
Answer:
a) MZ₂
b) They have the same concentration
c) 4x10⁻⁴ mol/L
Explanation:
a) The solubility (S) is the concentration of the salt that will be dissociated and form the ions in the solution, the solubility product constant (Kps) is the multiplication of the concentration of the ions elevated at their coefficients. The concentration of the ions depends on the stoichiometry and will be equivalent to S.
The salts solubilization reactions and their Kps values are:
MA(s) ⇄ M⁺²(aq) + A⁻²(aq) Kps = S*S = S²
MZ₂(aq) ⇄ M⁺²(aq) + 2Z⁻(aq) Kps = S*S² = S³
Thus, the Kps of MZ₂ has a larger value.
b) A saturated solution is a solution that has the maximum amount of salt dissolved, so, the concentration dissolved is solubility. As we can notice from the reactions, the concentration of M⁺² is the same for both salts.
c) The equilibrium will be not modified because the salts have the same solubility. So, let's suppose that the volume of each one is 1 L, so the number of moles of the cation in each one is 4x10⁻⁴ mol. The total number of moles is 8x10⁻⁴ mol, and the concentration is:
8x10⁻⁴ mol/2 L = 4x10⁻⁴ mol/L.
