You have to start listing from the bottom :
3. Secondary Consumers
2. Primary Consumers
1. Producer
In order to see which species has the strongest dispersion forces, you need to calculate their molar mass, because the higher the molar mass, the stronger the dispersion forces.
Since E. C8H18 has the highest molar mass, its dispersion forces are also the strongest ones.
Answer:
A buffer system can be made by mixing a soluble compound that contains the conjugate ... 10.0 grams of sodium acetate in 200.0 mL of 1.00 M acetic acid.
Explanation:
Answer:
0.0554 moles of NaCl are produced from the reaction of 1.67*10²² molecules of Na₂CO₃ with excess HCl.
Explanation:
The balanced reaction is:
Na₂CO₃ + 2 HCl → 2 NaCl + CO₂ + H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:
- Na₂CO₃: 1 mole
- HCl: 2 moles
- NaCl: 2 moles
- CO₂: 1 mole
- H₂O: 1 mole
On the other hand, Avogadro's Number is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number applies to any substance.
In this case, you can apply the following rule of three: if 6.023*10²³ molecules of Na₂CO₃ are contained in 1 mole, 1.67*10²² molecules will be contained in how many moles?

amount of moles= 0.0277 moles
In this case, you can apply the following rule of three: if by stoichiometry 1 mole of Na₂CO₃ produces 2 moles of NaCl, 0.0277 moles of Na₂CO₃ will produce how many moles of NaCl?

amount of moles of NaCl= 0.0554 moles
<u><em>0.0554 moles of NaCl are produced from the reaction of 1.67*10²² molecules of Na₂CO₃ with excess HCl.</em></u>
Noble Gas Cores have following electronic configuration
He = 1s²
Ne = [He] 2s², 2p⁶
Ar = [Ne] 3s², 3p⁶
Kr = [Ar] 4s², 4p⁶
Xe = [Kr] 5s², 5p⁶
Now solving for question elements,
Germanium = Ge = [Ar] 3d¹⁰, 4s², 4p²
Nickle = Ni = [Ar] 3d¹⁰, 4s²
Tunsten = W = [Xe] 4f¹⁴, 5d⁴, 6s²
Titanium = Ti = [Ar] 3d², 4s²
Iron = Fe = [Ar] 3d⁶, 4s²
Zinc = Zn = [Ar] 3d¹⁰, 4s²