Answer:
116.3 kJ
Step-by-step explanation:
Three heat transfers are involved
q = Heat to warm ice + heat to melt ice + heat to warm water + heat to evaporate water + heat to warm steam
q = q₁ + q₂ + q₃ + q₄ + q₅
q = mC₁ΔT₁ + mΔH_fus + mC₃ΔT₃ + mΔH_vap + mC₅ΔT₅
<em>Step 1</em>: Calculate q₁
m = 37.0 g
C₁ = 2.010 J·°C⁻¹g⁻¹
ΔT₁ = T_f – T_i
ΔT₁ = 0.0 – (-10.0)
ΔT₁ = 10.0 °C
q₁ = 37.0 × 2.010 × 10.0
q₁= 743.7 J
q₁= 0.7437 kJ
===============
<em>Step 2</em>. Calculate q₂
ΔH_fus = 334 J/g
q₂ = 37.0 × 334
q₂ = 12 360 J
q₂ = 12.36 kJ
===============
Step 3: Calculate q₃
C₃ = 4.179 J·°C⁻¹g⁻¹
ΔT₃ = T_f – T_i
ΔT₃ = 100 – 0
ΔT₃ = 100 °C
q₃ = 37.0 × 4.179 × 100
q₃ = 15 460 J
q₃ = 15.46 kJ
===============
<em>Step 4</em>. Calculate q₄
ΔH_vap = 2260 J/g
q₄ = 37.0 × 2260
q₄ = 83 620 J
q₄ = 83.62 kJ
===============
<em>Step 5</em>. Calculate q₅
C¬₅ = 2.010 J·°C⁻¹g⁻¹
ΔT₅ = T_f – T_i
ΔT₅ = 155.0 – 1000
ΔT₅ = 55.0 °C
q₅ = 37.0 × 2.010 × 55
q₅ = 4090 J
q₅ = 4.090 kJ
===============
Step 6. Calculate q
q = 0.7437 + 12.36 + 15.46 + 83.62 + 4.090
q = 116.3 kJ
The heat required is 116.3 kJ.
<u>Answer:</u> The correct answer is heat will flow from the boiling water into the frozen metal.
<u>Explanation:</u>
According to the law of conservation of energy, energy cannot be destroyed nor created but it can be transformed from 1 form to another form.
There are 3 processes of heat transfer:
- <u>Conduction:</u> This type of heat transfer occurs when there is direct contact between the two objects.
- <u>Convection:</u> This type of heat transfer occurs when there is a movement of fluid (liquid or gas) due to the movement of hot layers to the top and cold layers to the bottom which leads to convection currents.
- <u>Radiation:</u> This type of heat transfer occurs when there is a direct transfer of energy through space.
The heat moves from a hot surface to a cold surface to maintain equilibrium.
We are given:
A metal is placed in a freezer (cold object) and another metal is placed in an oven (hot object) and then both the metals are placed in boiling water.
Initially, the heat will flow from the boiling water (hot object) into the frozen metal (cold object) to maintain equilibrium
Hence, the correct answer is heat will flow from the boiling water into the frozen metal.
Answer : The density of an object is 0.93 g/mL
Explanation : Given,
Mass of an object = 3.8 g
Initial volume = 4.5 mL
Final volume = 8.6 mL
First we have to calculate the volume of an object.
Volume of an object = Final volume - Initial volume
Volume of an object = 8.6 mL - 4.5 mL
Volume of an object = 4.1 mL
Now we have to calculate the density of an object.
Formula used:

Now putting all the given values in this formula, we get:


Therefore, the density of an object is 0.93 g/mL
Answer:
3
Explanation:
10.0 has 3 significant figures
Answer:
10.76 grams
Explanation:
Given that the amount of
is 25.0 grams.
Mass of 1 mole of
= 158 grams
The number of atoms in 1 mole of
is 4.
Mass of oxygen in 1 mole of
= 16\times 4 = 68 grams.
Here, 158 grams of
has 68 grams of oxygen
So, the amount of oxygen in 1 gram of
= 68/158 grams
Therefore, the amount of oxygen in 1 gram of
=
grams
=10.76 grams
Hence, 25 grams of
has 10.76 grams of oxygen.