He, ne , Ar - Noble gas elements have the highest ionization energy,
while francium (87) has the lowest ionization energy because it is so far from helium, in short atom near to helium has higher ionization energy and the atom who is far away from helium have low ionization energy.
Please let me know if you have any questions
1. 2Al(s)+6HCl(aq)⇒2AlCl₃(aq)+3H₂(g)
2. 2AgNO₃ (aq) + Cu (s)⇒Cu(NO₃)₂ (aq) + 2Ag (s)
3. 2C₃H₈O(l) + 9O₂(g) ⇒ 6CO₂(g) + 8H₂O(g)
<h3>Further explanation</h3>
There are several reactions that can occur in a chemical reaction: single replacement, double replacement, synthesis, decomposition or combustion, etc.
1.Al(s)+HCl(aq)⇒AlCl₃(aq)+H₂(g)
type : single replacement
balance :
2Al(s)+6HCl(aq)⇒2AlCl₃(aq)+3H₂(g)
2. AgNO₃ (aq) + Cu (s) ⇒ Cu(NO₃)₂ (aq) + Ag (s)
type : single replacement
balance :
2AgNO₃ (aq) + Cu (s)⇒Cu(NO₃)₂ (aq) + 2Ag (s)
3. C₃H₈O + O₂ ⇒ CO₂ + H₂O
type : combustion of alcohol
balance :
2C₃H₈O(l) + 9O₂(g) ⇒ 6CO₂(g) + 8H₂O(g)
Answer:
P = 995.6 atm
Explanation:
assuming ideal gas:
∴ Tst = 25°C ≅ 298 K
∴ V = 35.00 mL = 0.035 L
∴ molar mass CO2 = 44.01 g/mol
∴ mass CO2(g) = 62.76 g
⇒ mol CO2(g) = (62.76 g)*(mol/44.01 g) = 1.426 mol
∴ R = 0.082 atm.L/K.mol
⇒ P = RTn/V
⇒ P = ((0.082 atm.L/K.mol)*(298 K)*(1.426 mol)) / (0.035 L)
⇒ P = 995.6 atm
Well you can’t answer because there’s no question, just data. What’s the specific question you’re trying to answer?