The mass of CO₂ gas produced during the combustion of one gallon of octane is 8.21 kg.
The given parameters:
- <em>Density of the octane, ρ = 0.703 g/ml</em>
- <em>Volume of octane, v = 3.79 liters</em>
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The mass of the octane burnt is calculated as follows;
The combustion reaction of octane is given as;
From the reaction above:
228.46 g of octane -------------------> 704 g of CO₂ gas
2,664.37 of octane --------------------> ? of CO₂ gas
Thus, the mass of CO₂ gas produced during the combustion of one gallon of octane is 8.21 kg.
Learn more about combustion of organic compounds here: brainly.com/question/13272422
Is go be 4x=7 so when you see yo thing pick the 2nd one it's go be b
EVERYDAY MANS ON THE BLOCK. Lol its 4. You got this from Mans Not Hot, didn't you? xD
4. <span>The metals that would be able to reduce copper ions in solution would be hydrogen(H), lead(Pb), tin(Sb), nickel(Ni), iron(Fe), zinc(Zn), aluminum(Al), Magnesium(Mg), sodium(Na), calcium(Ca), potassium(K), and lithium(Li).
5. </span>If you had a house with both copper- and zinc-galvanized iron water pipes,zinc would be desirable because <span>A metal that is easily oxidized would rust more readily.</span><span>
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The nails can puncture the tires of the vehicles making them deflated after a while. The process of tire deflation due to a puncture is due to the process called an effusion. Thus, option c is correct.
<h3>What is effusion?</h3>
Effusion is the process that defines the escape of the fluids or gases from a system through an outlet with a small diameter compared to the mean free path of the molecules.
When a tire is punctured then the gas from the tire starts to move out through the hole through effusion. This leads to deflation of the tire after some time as all the gas present inside had moved out completely.
Therefore, option c. a punctured tire deflates due to effusion.
Learn more about effusion here:
brainly.com/question/2823560
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