Question

Consider the following intermediate chemical equations. 2 equations: first: upper C (s) plus one-half upper O subscript 2 (g) right arrow upper C upper O (g). Second: upper C upper O (g) plus one-half upper O subscript 2 (g) right arrow upper C upper O subscript 2 (g). When you form the final chemical equation, what should you do with CO? Cancel out CO because it appears as a reactant in one intermediate reaction and a product in the other intermediate reaction. Add the two CO molecules together, and write them as reactants in the final chemical reaction. Write CO only once as a reactant in the final chemical reaction. Write CO as a reactant and a product in the final chemical reaction.

Answer 1

Answer:

The correct answer is ;

Cancel out CO because it appears as a reactant in one intermediate reaction and a product in the other intermediate reaction.

The final chemical reaction:

$C(s)+1O_2+\rightarrow CO_2(g)$

Explanation:

Step 1 :

$C(s)+\frac{1}{2}O_2(g)\rightarrow CO(g)$..[1]

Step 2:

$CO(g)+\frac{1}{2}O_2(g)\rightarrow CO_2(g)$..[2]

Adding equation [1] and [2] will give us final equation :

$C(s)+\frac{1}{2}O_2(g)+\frac{1}{2}O_2(g)+CO(g)\rightarrow CO(g)+CO_2(g)$

CO (g) on both sides will get cancel and the final equation comes out to be :

$C(s)+1O_2+\rightarrow CO_2(g)$

CO as a reactant and a product in the final chemical reaction is written as:

$C(s)+1O_2(g)+CO(g)\rightarrow CO_2(g)+(CO(g)$

Answer 2

Answer:

D

Explanation:

edg 2020 unit test