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3 years ago

Calculate the frequency of a ray of light with an energy of 5.5 x 10-19 joules

Chemistry

1 answer:

Akimi4 [234]3 years ago

7 0

Answer:

f = 0.83 ×10¹⁵s⁻¹

Explanation:

Given data:

Energy of ray = 5.5 ×10⁻¹⁹ J

Frequency = ?

Solution:

Formula:

E = hf

f = E/h

J = Kg . m².s⁻²

f = 5.5 ×10⁻¹⁹ Kg . m².s⁻² / 6.63 ×10⁻³⁴ m²Kg/s

f = 0.83 ×10¹⁵s⁻¹

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How many molecules of hydrogen gas (Hz) are needed to produce 9.0 x 1023 molecules of H2O?

VashaNatasha [74]

Answer:

Explanation: Ammonia (NH3) is produced by the reaction of nitrogen gas and hydrogen gas. ... How many grams of fluorine gas are needed to produce 100.00g of AlF3? ... How many molecules of CO2 gas can be produced of 156.24g of benzene, ... (a) If 16.74.g of Fe and 9.0 9 of H2O are allowed to react, how many grams of products.

4 0

3 years ago

In the laboratory a student combines 26.2 mL of a 0.234 M chromium(III) acetate solution with 10.7 mL of a 0.461 M chromium(III)

Natalka [10]

Answer: The molarity of $Cr^{3+}$ ions in the solution is 0.299 M

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}$ .....(1)

For chromium (III) acetate:

Molarity of chromium (III) acetate solution = 0.234 M

Volume of solution = 26.2 mL

Putting values in equation 1, we get:

$0.234=\frac{\text{Moles of chromium (III) acetate}\times 1000}{26.2}\\\\\text{Moles of chromium (III) acetate}=\frac{0.234\times 26.2}{1000}=0.00613mol$

1 mole of chromium (III) acetate $(Cr(CH_3COO)_3)$ produces 1 mole of chromium $(Cr^{3+})$ ions and 3 moles of acetate $(CH_3COO^-)$ ions

Moles of $Cr^{3+}\text{ ions}=(1\times 0.00613)=0.00613moles$

For chromium (III) nitrate:

Molarity of chromium (III) nitrate solution = 0.461 M

Volume of solution = 10.7 mL

Putting values in equation 1, we get:

$0.461=\frac{\text{Moles of chromium (III) nitrate}\times 1000}{10.7}\\\\\text{Moles of chromium (III) nitrate}=\frac{0.461\times 10.7}{1000}=0.00493mol$

1 mole of chromium (III) nitrate $(Cr(NO_3)_3)$ produces 1 mole of chromium $(Cr^{3+})$ ions and 3 moles of nitrate $(NO_3^-)$ ions

Moles of $Cr^{3+}\text{ ions}=(1\times 0.00493)=0.00493moles$

For chromium cation:

Total moles of chromium cations = [0.00613 + 0.00493] = 0.01106 moles

Total volume of solution = [26.2 + 10.7] = 36.9 mL

Putting values in equation 1, we get:

$\text{Molarity of }Cr^{3+}\text{ cations}=\frac{0.01106\times 1000}{36.9}\\\\\text{Molarity of }Cr^{3+}\text{ cations}=0.299M/tex]Hence, the molarity of [tex]Cr^{3+}$ ions in the solution is 0.299 M

5 0

4 years ago

CHEM PLZ HELP

marusya05 [52]

Answer:

Increase in CO2 (g) over time.

No NaHCO3 (s) will be left after a time

Explanation:

The reaction, shown below;

2NaHCO3(s) → Na2CO3(s)+CO2(g)+H2O(ℓ) is a decomposition reaction. A decomposition reaction is a kind of chemical reaction in which a given chemical specie breaks up to give other chemical species. Decomposition may be induced by heat or light.

Usually, there is only one reactant in a decomposition reaction; the specie that disintegrates into the products. This reactant usually decreases in concentration steadily because it is converted into products. This is why the mass of NaHCO3(s) in the system continues to decrease steadily until it finally falls to zero.

Conversely, the concentration (for aqueous) or volume (for gases) or mass (for solid) products of the reaction increases steadily as the reaction progresses. This explains why the volume of CO2 in the system will steadily increase over time.

7 0

3 years ago

How can you distinguish a clastic sedimentary rock from a crystalline formed sedimentary rock?

Ket [755]

: A clastic sedimentary rock will be full of... clasts. Pieces of shells, ooids, pizoids, etc. A chemically formed sedimentary rock may have these but it will dominantly be a layered rock, you should be able to see concentric layers

6 0

3 years ago

2SO3(g)⟶2S(s)+3O2(g)ΔH=+790kJ. How many kilojoules are required when 2.1 moles of SO3 reacts?

guapka [62]

Given:

Enthalpy change (ΔH) for SO3 decomposition = +790 kJ

Moles of SO3 = 2.1 moles

To determine:

Energy required when 2.1 moles of SO3 reacts

Explanation:

The decomposition reaction is -

2SO3(g) → 2S(s) + 3O2 (g)

Energy required when 2 moles of SO3 reacts is 790 kJ

Thus, for 2.1 moles of SO3 the energy requirement would be

= 2.1 moles SO3 * 790 kJ/2 moles SO3 = 829.5 kJ

Ans: 830 kJ are required when 2.1 moles of SO3 reacts.

4 0

3 years ago

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