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3 years ago

NEED ASAP. WILL MARK BRAINLIEST!

Chemistry

2 answers:

Nesterboy [21]3 years ago

7 0

Answer:

B. Matter is composed of very small particles.

Explanation:

All matter is composed of extremely small particles called atoms. All atoms of a given element are identical in size, mass,

crimeas [40]3 years ago

7 0

Answer:

Explanation:

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3 miles of NaCl in 12 liters of water What is the molarity

lesya [120]

Answer:

$12 \: litres \: contain \: 3 \: \: moles \: of \: sodium \: chloride \\ 1 \: litre \: will \: contain \: \frac{(1 \times 3)}{12} moles \\ = 0.25 \: mol \: {l}^{ - 1}$

Explanation:

$12 \: litres \: contain \: 3 \: \: moles \: of \: sodium \: chloride \\ 1 \: litre \: will \: contain \: \frac{(1 \times 3)}{12} moles \\ = 0.25 \: mol \: {l}^{ - 1} \\ or : 0.25 \: M$

8 0

3 years ago

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using the periodic table, predict which element-potassium, aluminum, or iron-is most reactive. explain your answer.

charle [14.2K]

Potassium is more reactive because it is in group one

4 0

3 years ago

What type of bond exists between the atoms in a molecule of N2?

vivado [14]

Answer:

covalent bonds

Explanation:

Nitrogen atoms will form three covalent bonds (also called triple covalent) between two atoms of nitrogen because each nitrogen atom needs three electrons to fill its outermost shell.

(if it is still confusing i have another way of explaining so jus let me know :)

6 0

3 years ago

A sample of 9.27 g9.27 g of solid calcium hydroxide is added to 38.5 mL38.5 mL of 0.500 M0.500 M aqueous hydrochloric acid. Writ

navik [9.2K]

Answer: The excess reagent for the given chemical reaction is calcium hydroxide and the amount left after the completion of reaction is 0.115375 moles. The amount of calcium chloride formed in the reaction is 1.068 grams.

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ....(1)

For calcium hydroxide:

Given mass of calcium hydroxide = 9.27 g

Molar mass of calcium hydroxide = 74.093 g/mol

Putting values in above equation, we get:

$\text{Moles of calcium hydroxide}=\frac{9.27g}{74.093g/mol}=0.125mol$

To calculate the moles of a solute, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

We are given:

Volume of hydrochloric acid = 38.5mL = 0.0385 L (Conversion factor: 1 L = 1000 mL)

Molarity of the solution = 0.500 moles/ L

Putting values in above equation, we get:

$0.500mol/L=\frac{\text{Moles of hydrochloric acid}}{0.0385L}\\\\\text{Moles of hydrochloric acid}=0.01925mol$

For the given chemical equation:

$2HCl(aq.)+Ca(OH)_2(s)\rightarrow CaCl_2(s)+2H_2O(l)$

Here, the solid salt is calcium chloride.

By Stoichiometry of the reaction:

2 moles of hydrochloric acid reacts with 1 mole of calcium hydroxide.

So, 0.01925 moles of hydrochloric acid will react with = $\frac{1}{2}\times 0.01925=0.009625moles$ of calcium hydroxide.

As, given amount of calcium hydroxide is more than the required amount. So, it is considered as an excess reagent.

Thus, hydrochloric acid is considered as a limiting reagent because it limits the formation of product.

Amount of excess reagent (calcium hydroxide) left = 0.125 - 0.01925 = 0.115375 moles

By Stoichiometry of the reaction:

2 moles of hydrochloric acid produces 1 mole of calcium chloride.

So, 0.01925 moles of hydrochloric acid will produce = $\frac{1}{2}\times 0.01925=0.009625moles$ of calcium chloride.

Now, calculating the mass of calcium chloride from equation 1, we get:

Molar mass of calcium chloride = 110.98 g/mol

Moles of calcium chloride = 0.009625 moles

Putting values in equation 1, we get:

$0.009625mol=\frac{\text{Mass of calcium chloride}}{110.98g/mol}\\\\\text{Mass of calcium chloride}=1.068g$

Hence, the excess reagent for the given chemical reaction is calcium hydroxide and the amount left after the completion of reaction is 0.115375 moles. The amount of calcium chloride formed in the reaction is 1.068 grams.

5 0

3 years ago

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7. A spontaneous reaction occurs when the sign of free energy IS

il63 [147K]

Answer:

positive

Explanation:

3 0

2 years ago