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xeze [42]
3 years ago
13

20 Points! Please Help!

Mathematics
1 answer:
ivolga24 [154]3 years ago
3 0

To solve this problem yo need to have the "x", the "y", and the radius. To find the radius since it is not given we use the formula.

sq rt(-3^2+1^2)

sq rt(9+1)

sq rt(10) would be the length of the radius in this case.

Then we use the sine cosine and tangent fractions

sin:y/r

cos:x/r

tan:y/x

With the values plugged in the equations are

SIN:1/sqrt(10) Since there can´t be a sq rt in hte denominator we change it to 1(sq rt(10))/10

COS:-3/sqrt(10) Since there can´t be a sq rt in the denominator we change it to -3(sq rt(10))/10

TAN:1/-3 This one can stay the same.

This would be the measures of SIN, COS, and TAN.

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I am in the same row as 83 you say me when you start at 10 and count by tens.
yKpoI14uk [10]

Answer:90

Step-by-step explanation:

10,20,30,40,50,60,70,80,90,100

Counting in tens the same row as 83 is 90 .

5 0
3 years ago
I have trouble with the converting
Gnom [1K]
HI,
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7 0
4 years ago
Factor as the product of two binomials.<br><br> 9 - 6x + x^2
Masja [62]
It is
(3-x)^2
i made sure it correct this time
3 0
3 years ago
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2\3x20<br><br> 20 points thx
Ivenika [448]

Answer:

13.3333333333

Step-by-step explanation:

hope this helps

6 0
3 years ago
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What is the better buy?
White raven [17]

Answer: Option B is the cheaper deal (the 12 batteries for $14.76)

===========================================================

Explanation:

For the first deal we can say

3 batteries = 4.80 dollars

3/3 batteries = 4.80/3 dollars .... divide both sides by 3

1 battery = 1.60 dollars

The unit price for the first deal is $1.60 per battery.

----------------------------------

For the second deal we could say

12 batteries = 14.76 dollars

12/12 batteries = 14.76/12 dollars .... divide both sides by 12

1 battery = 1.23 dollars

The unit price for the first deal is $1.23 per battery.

This is the cheaper deal.

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So in short, you're dividing the total cost over the number of items to get the unit price.

4 0
3 years ago
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