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Ierofanga [76]
4 years ago
12

A girl is delivering newspapers travels 3 km north, 3 km west and 5 km south. What is the total distance that she travels?

Physics
2 answers:
Vedmedyk [2.9K]4 years ago
8 0

Answer:

She travels a total of 11 km

UNO [17]4 years ago
6 0

She travels 11 km

I hope I helped

:D

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If the capacity of the lungs of an adult were 3.8 L, how many moles of air would the lungs contain at body temperature and atmos
Ahat [919]

Answer:

  • 0.14955  mol

Explanation:

We can solve this problem using the ideal gas law

P \ V = \ n \ R \ T

where P is the pressure, V the volume, n the number of moles, R the ideal gas constant and T the temperature.

We can use the atmospheric pressure as 1 atm, and the body temperature as 36.5 °C, in Kelvin this is:

T_{body} = 36.5 \° C = (36.5 + 273.15) K = 309.65 \ K

The ideal gas constant is:

R = 0.082057 \frac{L \ atm}{ K \ mol}

taking all this in consideration, the number of moles will be:

n = \frac{P \ V}{  R \ T }

n = \frac{1 \ atm * 3.8 \ L  }{ 0.082057 \frac{L \ atm}{ K \ mol} *  309.65 \ K } [/tex]

n = 0.14955 \ mol

3 0
3 years ago
If a car travels 30 kilometers in 2 hours, it’s average speed is?
7nadin3 [17]

Answer:

15km/h

Explanation:

Time taken to complete 30km/h=2 hours=15km/h hence the average speed is 15km/h.

5 0
3 years ago
What will change the velocity of a periodic wave?
Travka [436]

Changing the medium of the wave.

Waves is always determined by the properties of the medium, which means that changing the medium will change the velocity of the wave


7 0
3 years ago
Read 2 more answers
A 481-m long spaceship passes by an observer at the speed of 2.70×10^8 m/s. What length does the observer measure for the spaces
galben [10]

Answer:

209.66 m

Explanation:

Given:

Original length of the spaceship, L = 481 m

Speed of the spaceship, v = 2.70 × 10⁸ m/s

Now,

using the concept of length contraction, we have

L=\frac{L'}{\sqrt{1-\frac{v^2}{c^2}}}

where,

L' is the observed length

c is the speed of the light

Thus,

on substituting the respective values, we get

481=\frac{L'}{\sqrt{1-\frac{(2.70\times10^8)^2}{(3\times10^8)^2}}}

or

L'  = 209.66 m

3 0
4 years ago
Force F acts between two charges, q1 and q2, separated by a distance d. If q1 is increased to twice its original value and the d
Step2247 [10]
Okay, haven't done physics in years, let's see if I remember this.

So Coulomb's Law states that F = k \frac{Q_1Q_2}{d^2} so if we double the charge on Q_1 and double the distance to (2d) we plug these into the equation to find

<span>F_{new} = k \frac{2Q_1Q_2}{(2d)^2}=k \frac{2Q_1Q_2}{4d^2} = \frac{2}{4} \cdot k \frac{Q_1Q_2}{d^2} = \frac{1}{2} \cdot F_{old}</span>

So we see the new force is exactly 1/2 of the old force so your answer should be \frac{1}{2}F if I can remember my physics correctly.

9 0
4 years ago
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