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mylen [45]
4 years ago
11

What happens when an object with a higher density is placed in a container with a lower density liquid?

Physics
1 answer:
svetoff [14.1K]4 years ago
8 0
The object with the higher density sinks to the bottom and the lower density stays at the top.They don't mix together either because, of the type of density.
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Kinetic energy is the energy of ______. It increases with mass ______ and _______ .Potential energy is the energy of _______or__
Alona [7]

Answer:

velocity.  height. weight. possition. place. energy. force.

Explanation: 50/50 % chance they are wrong and write.

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Which of the following is NOT a possible cause of a genetic disorder in humans?
DanielleElmas [232]
Im pretty sure the answer is mutations in the DNA of genes because i believe the other 3 are correct 
4 0
4 years ago
If I push on the wall with 75 Newtons of force, the wall will push back with ______
Sauron [17]

Answer:

(F)reaction = - 75 N

where, negative sign shows opposite direction.

Explanation:

This question can be answered using Newton's third law of motion. The Newton's Third Law of Motion states that for every action force there is an equal but opposite reaction force.

(F)action = - (F)reaction

Hence, in our scenario if we consider the 75 Newton force applied on the wall to be the action force then the reaction force of the wall must be equal to it in opposite direction. Therefore, the reaction push of the wall must be equal to 75 N.

<u>(F)reaction = - 75 N</u>

<u>where, negative sign shows opposite direction.</u>

6 0
3 years ago
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deff fn [24]
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7 0
4 years ago
A ball bearing of radius of 1.5 mm made of iron of density
Serjik [45]

Answer:

\boxed{\sf Viscosity \ of \ glycerine \ (\eta) = 14.382 \ poise}

Given:

Radius of ball bearing (r) = 1.5 mm = 0.15 cm

Density of iron (ρ) = 7.85 g/cm³

Density of glycerine (σ) = 1.25 g/cm³

Terminal velocity (v) = 2.25 cm/s

Acceleration due to gravity (g) = 980.6 cm/s²

To Find:

Viscosity of glycerine (\sf \eta)

Explanation:

\boxed{ \bold{v =  \frac{2}{9}  \frac{( {r}^{2} ( \rho -  \sigma)g)}{ \eta} }}

\sf \implies \eta =  \frac{2}{9}  \frac{( {r}^{2}( \rho -  \sigma)g )}{v}

Substituting values of r, ρ, σ, v & g in the equation:

\sf \implies \eta =  \frac{2}{9}  \frac{( {(0.15)}^{2}  \times  (7.85 - 1.25) \times 980.6)}{2.25}

\sf \implies \eta =  \frac{2}{9}  \frac{(0.0225 \times 6.6 \times 980.6)}{2.25}

\sf \implies \eta =  \frac{2}{9}  \times  \frac{145.6191}{2.25}

\sf \implies \eta =  \frac{2}{9}  \times 64.7196

\sf \implies \eta =  2 \times 7.191

\sf \implies \eta =  14.382 \: poise

6 0
3 years ago
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