Question

You are looking at a map. Town A is at (4, 8) and town B is at (7, 17). What is the distance between the two towns (round to the nearest tenth)? If the scale used on the map is .5 units = 24 miles, how far apart are the cities in miles?

Answer 1

Answer:

470.4 Miles

Step-by-step explanation:

The distance between two points $(x_1,y_1) \& (x_2,y_2)$ is obtained using the distance formula:

Distance$=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Given Town A at (4, 8) and Town B is at (7, 17).

Distance between A and B is:

$AB=\sqrt{(7-4)^2+(17-8)^2}\\=\sqrt{(4)^2+(9)^2}\\AB=\sqrt{97} \approx 9.8\\ Since .5 Units=24 Miles\\1 Unit =48 Miles\\Therefore:\\9.8 Units = 9.8 X 48 =470.4 Miles$

The distance between AB is 470.4 Miles.