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Olenka [21]
3 years ago
9

You are looking at a map. Town A is at (4, 8) and town B is at (7, 17). What is the distance between the two towns (round to the

nearest tenth)? If the scale used on the map is .5 units = 24 miles, how far apart are the cities in miles?
Mathematics
1 answer:
victus00 [196]3 years ago
6 0

Answer:

470.4 Miles

Step-by-step explanation:

The distance between two points (x_1,y_1) \& (x_2,y_2) is obtained using the distance formula:

Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Given Town A at (4, 8) and Town B is at (7, 17).

Distance between A and B is:

AB=\sqrt{(7-4)^2+(17-8)^2}\\=\sqrt{(4)^2+(9)^2}\\AB=\sqrt{97} \approx 9.8\\$Since .5 Units=24 Miles\\1 Unit =48 Miles\\Therefore:\\9.8 Units = 9.8 X 48 =470.4 Miles

The distance between AB is 470.4 Miles.

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Outside: Means terms found in the outside areas of the whole equation, in this case it is 6x and 2
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Inside: Means terms found in the inside areas of the whole equation, in this case it is -2 and 6x
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Now you have what you need for your new equation:

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Because your second and third terms are like terms, you can combine them by doing the operation indicated. 12x-12x = 0 so now you can cancel it out from your equation and your left with:

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