Question

What is the surface area of a cone that has a radius of 8 feet and a slant height of 12 feet? (Use 3.14 for π.)

Answer 1

Answer:

Surface area of cone is $502.4\ ft^2$

Step-by-step explanation:

Given:

radius of a cone (r) = 8 feet

slant height of cone (l) = 12 feet

We need to find the surface area of cone.

Total surface area of cone = Area of circle $+$ Area of curved surface

Now we know that,

Area of circle = $\pi r^2$

Area of curved surface = $\pi rl$

Hence Total surface area of cone = $\pi r^2+\pi rl=\pi r(r+l) = 3.14 \times 8 (8+12)=3.14\times8\times20= 502.4 \ ft^2$

Surface area of cone is $502.4\ ft^2$.