Plss help me with this ASAP THX

Adam's Tea Shop has caffeinated tea and decaffeinated tea. The tea shop served 30 teas in all, 24 of which were caffeinated. Wha

Jobisdone [24]

Answer:percentage of the decaffeinated Tea =20%

Step-by-step explanation:

Number of teas sold in the tea shop =30

Number of caffeinated teas=24

Number of decaffeinated = Total teas sold -Number of caffeinatedteas

30-24=6

percentage of the decaffeinated Tea =6/30 x 100 =20%

4 0

3 years ago

Boyle's Law states that when a sample of gas is compressed at a constant temperature, the pressure P and volume V satisfy the eq

lawyer [7]

Answer:

The value of rate of decrease of volume = - 3600 $\frac{k pa}{min}$

Step-by-step explanation:

According to Boyle's law P V = C ------- (1)

Pressure ( P ) = 100 k pa = 10 $\frac{N}{cm^{2} }$

Volume ( V ) = 900 $cm^{3}$

Put these values in equation ( 1 ) we get,

⇒ C = 10 × 900 = 9000 N-cm = 90 N-m

Differentiate Equation ( 1 ) with respect to time we get,

⇒ V $\frac{dP}{dt}$ + P $\frac{dV}{dt}$ = 0

⇒ V $\frac{dP}{dt}$ = - P $\frac{dV}{dt}$

⇒ $\frac{dV}{dt}$ = - $\frac{V}{P}$ $\frac{dP}{dt}$ ---------- (2)

This equation gives the rate of decrease of volume.

Given that Rate of increase of pressure = $\frac{dP}{dt}$ = 40 $\frac{k pa}{min}$

C = 90 N-m

P = $10^{5}$ pa = 10 $\frac{N}{cm^{2} }$

V = 900 $cm^{3}$

Put all the above values in equation 2 we get,

⇒ $\frac{dV}{dt}$ = - $\frac{900}{10}$ × 40

⇒ $\frac{dV}{dt}$ = - 3600 $\frac{k pa}{min}$

This is the value of rate of decrease of volume.

8 0

3 years ago

The length of the base of a rectangular pyramid is tripled, the width of the base remains the same, and the height of the pyrami

Andre45 [30]

3 times length(l) times width(w) times height(h) over 7. So 3l • w • (h/7)

7 0

3 years ago

How many numbers are there from x through 7x-8

kondaur [170]

6x-7 is your answer

8 0

3 years ago

Enter your answer and show all the steps that you use to solve this problem in the space provided. A.Solve a–9=20 B.Solve b–9&gt

Goryan [66]

Answer:

A) The value of a is 29.

B) The value of b is greater than 29.

C) In both part A and part B we have used a common property which is addition property and that we have add 9 on both side of equation in both parts.

D) The value of a in part A is equal to 29 whereas in part B the value of b is greater than 29.

Step-by-step explanation:

Solving for Part A.

Given,

$a-9=20$

We have to solve for a.

$a-9=20$

By using addition property of equality, we will add both side by 9;

$a-9+9=20+9\\a=29$

Hence the value of a is 29.

Solving for Part B.

Given,

$b-9>20$

We have to solve for b.

$b-9>20$

By using addition property of inequality, we will add both side by 9;

$b-9+9>20+9\\b>29$

Hence the value of b is greater than 29.

Solving for Part C.

In both part A and part B we have used a common property which is addition property and that we have add 9 on both side of equation in both parts.

Solving for Part D.

The value of a in part A is equal to 29 whereas in part B the value of b is greater than 29.

5 0

3 years ago