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zheka24 [161]
3 years ago
14

Multi-step equations solve the equation

Mathematics
2 answers:
maria [59]3 years ago
6 0

Answer: Did you try to put the pic and it didn't come up right.

Step-by-step explanation:If you try to put pic from your phone it will not work but if you try to put it in chromebook it will work.

S_A_V [24]3 years ago
4 0
Can you be more specific please
You might be interested in
Xy+(4(20))>x-5y(2+9-7)
prohojiy [21]

I'll solve for y xy+(4(20))>x-5y(2+9-7) 

xy+4(20)>x-5y(2+9-7) 

xy+4(20)>x-5y(4) 

xy+4(20)>x-20y 

xy+80>x-20y 

xy+20y+80>x 

y(x+20)>-80+x 

y>(-80+x)/(x+20)


3 0
3 years ago
Hellohello, if you able to help me then please do. (:
Alja [10]
The answer is L < 5 .
5 0
3 years ago
QUESTION 1<br> What is the mean of 21, 23, 35, 40)?<br> o A. 27<br> B. 31.75<br> e C. 19<br> D.29.75
tangare [24]

Answer:

D. 29.75

Step-by-step explanation:

To determine the mean, you must add up all the numbers and then divide that number by how many numbers you added.

Here,

21 + 23 + 35 + 40

= 119

You added 4 numbers (21, 23, 35, 40),

so, 119 / 4

= 29.75

Hope this helps and a thank won't hurt! :)

3 0
3 years ago
0.2(-4–2.5b–7c). write the product
Xelga [282]

Answer:

-0.8 - 0.5b - 1.4c

Step-by-step explanation:

Take the b and the c away

Then times the 0.2 by all the numbers but don't add them

Once your done you and the b and c back to you equation

4 0
3 years ago
Given: A, B, and C What is the value of X in the matrix equation AX + B = C?
Ksju [112]

Answer:

Option (2)

Step-by-step explanation:

Given expression is, AX + B = C

A=\begin{bmatrix}-3 & -4\\ 1 & 0\end{bmatrix}

B=\begin{bmatrix}-7 & -9\\ 4 & -1\end{bmatrix}

C=\begin{bmatrix}-42 & -20\\ 5 & 4\end{bmatrix}

AX + B = C

AX = C - B

C - B = \begin{bmatrix}-42 & -20\\ 5 & 4\end{bmatrix}-\begin{bmatrix}-7 & -9\\ 4 & -1\end{bmatrix} = \begin{bmatrix}-42+7 & -20+9\\ 5-4 & 4+1\end{bmatrix}

C - B = \begin{bmatrix}-35 & -11\\ 1 & 5\end{bmatrix}

Let  X=\begin{bmatrix}a & b\\ c & d\end{bmatrix}

AX = \begin{bmatrix}-3 & -4\\ 1 & 0\end{bmatrix}\times \begin{bmatrix}a & b\\ c & d\end{bmatrix}

     = \begin{bmatrix}(-3a-4c) & (-3b-4d)\\ a & b\end{bmatrix}

Since AX = C - B

\begin{bmatrix}(-3a-4c) & (-3b-4d)\\ a & b\end{bmatrix}=\begin{bmatrix}-35 & -11\\ 1 & 5\end{bmatrix}

Therefore, a = 1, b = 5

(-3a - 4c) = -35

3(1) + 4c = 35

3 + 4c = 35

4c = 32

c = 8

And (-3b - 4d) = -11

3(5) + 4d = 11

4d = -4

d = -1

Therefore, Option (2). X = \begin{bmatrix}1 & 5\\ 8 & -1\end{bmatrix} will be the answer.

7 0
3 years ago
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