What are the two types of passive transport

Chemistry

2 answers:

sladkih [1.3K]3 years ago

8 0

They are DIFFUSION and OSMOSIS.

Simora [160]3 years ago

6 0

The two types of passive transport are simple diffusion and facilitated diffusion. Osmosis is a type of simple diffusion.

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Select the correct balanced oxidation-reduction reaction. Group of answer choices 14H+(aq) + 6Fe2+(aq) + Cr2O72-(aq) -> 6Fe3+

bezimeni [28]

Answer:

The correct balanced oxidation- reduction reaction is:

14H+(aq) + 6Fe2+(aq) + Cr2O72-(aq) -> 6Fe3+(aq) + 2Cr3+(aq) + 7H2O(l)

Explanation:

In this reaction, iron (Fe2+) is the reducing agent while Cr2O7^2- is the oxidizing agent.

The ion transfer is represented as shown below:

6 Fe 2+ - 6e- -----------> 6 Fe 3+ (oxidation)

2 Cr^6 + 6e^- ----------> 2 Cr^3 (reduction)

From the unbalanced reaction

Fe2+ + Cr2O72- + H+ ----------> Fe3+ + Cr3+ + H2O we will follow these steps to balance the reaction.

Step 1: break the equation into two half reactions stating which is oxidized and reduced.

Step 2: Balance the atoms on each sides; the hydrogen, oxygen

Step 3: Balance the gain also

Step 4: Give the electron gained on one side to be equal to the electron lost on the other side.

Step 5: Add the two half reactions and simplify the equation.

Doing this, we obtain

14H+(aq) + 6Fe2+(aq) + Cr2O72-(aq) -> 6Fe3+(aq) + 2Cr3+(aq) + 7H2O(l)

6 0

3 years ago

How many moles of chlorine are in 6.67x10^40 chlorine molecules?

sweet-ann [11.9K]

To solve for the number of moles, we simply have to use the Avogadros number which states that there are 6.022 x 10^23 molecules per mole. Therefore:

number of moles = 6.67 X 10^40 chlorine molecules / (6.022 x 10^23 molecules / mole)
number of moles = 1.108 x 10^17 moles

4 0

4 years ago

Read 2 more answers

The formation constant for the reaction ag (aq) 2nh3(aq) ag(nh3)2 (aq) is kf = 1.7 × 107 at 25°c. what is δg° at this temperatur

anzhelika [568]

The value of ΔG° at this temperature is -18034.18 J/mol

Calculation,

Given information

formation constant (Kf)= 1.7 × $10^{7}$