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SOVA2 [1]
3 years ago
12

Determine the number of atoms in 3.62 mL of mercury. The density of mercury is 13.5g/mL

Chemistry
1 answer:
vladimir1956 [14]3 years ago
3 0
=3.62 * 13.5
then you'll get mass.
then devide by molar mass of Hg
then multiply by avegadro number.(L)

get the answer .
hope this would help u
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scandium47 has a half-life of 35s. suppose you have a 45g sample of scadium 47 how much of the sample remains unchanged after 14
Mars2501 [29]

 The much  of the sample that would remain  unchanged  after 140 seconds is 2.813 g

Explanation

Half life  is time taken for the quantity  to reduce  to half its original value.

if the half life  for Scandium  is 35 sec, then the number  of half life in 140 seconds

=140 sec/ 35 s = 4 half life

Therefore 45 g after first half life = 45 x1/2 =22.5 g

               22.5 g after second half life = 22.5 x 1/2 =11.25 g

            11.25 g after third half life = 11.25 x 1/2 = 5.625 g

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therefore 2.813 g  of Scandium 47 remains  unchanged.

4 0
2 years ago
Changes in temperature can often cause a change in the state of matter of objects. A decreasein temperature causes which of the
STALIN [3.7K]

Answer:

B. Water will freeze

<em>because</em><em> </em><em>the</em><em> </em><em>latent</em><em> </em><em>heat</em><em> </em><em>of</em><em> </em><em>vapourization</em><em> </em><em>decreases</em><em>.</em>

5 0
2 years ago
What is commonly used to run a central heating system?
Troyanec [42]
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Explanation :-
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7 0
2 years ago
Using the equation, C5H12 + 8O2 Imported Asset 5CO2 + 6H2O, if an excess of pentane (C5H12) were supplied, but only 4 moles of o
ser-zykov [4K]
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</span>
Reason:
Reaction involved in present case is:
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In above reaction, 1 mole of C5H12 reacts with 8 moles of oxygen to give 6 moles of water.

Thus, 4 moles of oxygen will react with 0.5 mole of C5H12, to generate 3 moles of H2O.</span>
7 0
3 years ago
Read 2 more answers
Unknown # 41
sveta [45]

Answer:

KI

Explanation:

From the question, we can see that a qualitative analysis of the compound shows that it has a lilac flame colour. The lilac flame colour corresponds to the potassium ion (K^+).

Again, the test of addition of HNO3(aq) and AgNO3(aq) to a solution is a test for halogens. If the result is a green precipitate, then the ion present is the iodide ion (I^-).

Hence, the compound must be KI.

4 0
2 years ago
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