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Svetllana [295]
3 years ago
11

A certain gas is present in a 13.0 l cylinder at 4.0 atm pressure. if the pressure is increased to 8.0 atm , the volume of the g

as decreases to 6.5 l . find the two constants ki, the initial value of k, and kf, the final value of k, to verify whether the gas obeys boyle's law. express your answers to two significant figures separated by a comma.
Chemistry
2 answers:
Travka [436]3 years ago
8 0

Answer:

Yes, gas is obeying the Boyle's law.

Explanation:

Boyle's Law  states that 'pressure is inversely proportional to the volume of the gas at constant temperature and number of moles'.

P\propto \frac{1}{V}     (At constant temperature and number of moles)

P_1V_2 = constant=k=P_2V_2

Initial volume of the gas = V_1=13.0L

Initial pressure of the gas = P_1=4.0 atm

Initial value of k :

k_i=P_1V_1=4 atm \times 13.0 L =52 atm l

Final volume of the gas = V_2=6.5 L

Final pressure of the gas = P_2=8.0 atm

Final value of k :

k_f=P_2V_2=8.0 atm \times 6.5 L =52 atm l

k_i=k_f=52 atm L

As we can see that initial value of k is equal to the final value of k which means that gas is obeying the Boyle's law.

ella [17]3 years ago
5 0
<span>Boyle's Law is k = PV so Initial k = 13.0 L x 4.0 atm = 52 L atm Final kf = 6.5 L x 8 atm = 52 L atm The gas obeys Boyle's Law The answer with two significant figures separated by a comma is k = 52, kf = 52.</span>
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Answer:

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Explanation:

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This is intensive quantity as it is fixed for 1 mole .

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The value of these quantities does not get halve if you divide the substance into two equal parts. example , density, refractive index.

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Hence for this reaction :

2H_{2}(g)+O_{2}\rightarrow 2H_{2}(l)

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And here two moles are present . so the value of molar enthalpy is:

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8 0
3 years ago
What is the coefficient for hydrogen in the balanced equation for the reaction of solid molybdenum(iv) oxide with gaseous hydrog
anastassius [24]

The  coefficient  for hydrogen  in  the  balanced  equation   of solid  molybdenum(iV)  oxide  with gaseous  hydrogen  is  2


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MoO2  + 2 H2→  Mo  +2 H2O

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3 years ago
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den301095 [7]
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Answer:

1.The Aluminum block

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In this question it is important to remember that density of an object is the mass of that object divided by its volume.

The expression applied here is density=mass/volume

Given that the mass is constant,lets say mass= m=1g

and density of aluminum=2.7g/cm³ and that of iron is 7.8 g/cm³ then volume=?

Volume=mass/density

Volume of aluminum= 1/2.7 =0.3704 cm³

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Here we see volume of Aluminum block is the largest.

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katen-ka-za [31]

Answer:

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Explanation:

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