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eimsori [14]
3 years ago
9

When we study the earth and its people, we are studying ___________________. a) desalination b) geography c) irrigation d) absol

ute location
Physics
2 answers:
Fofino [41]3 years ago
7 0
Geography Earth studying
lbvjy [14]3 years ago
7 0
The answer is b geography
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Describe different types of motion with examples. (4)
Illusion [34]

Answer:

a)

there r two types of motion, uniform and non-uniform

uniform means equal distance travelled at equal intervals of time

and non-uniform is exactly the opposite.

b)

quantities which can be represented by magnitude along r called scalar quantities such as speed.

quantities which need magnitude along with direction r called vector quantities such as velocity.

c)

velocity=10m/s

acceleration = u-v/s i.e initial final velocity - initial velocity upon time

acceleration= 0.2m/s sq

time= 30s

10 = displacement/time

10 = x/30

10 = 300

Answer is 300 meters - distance/displacement.

8 0
3 years ago
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Suppose you are walking home after school. The distance from school to your home is five kilometers. On
Rudiy27
On foot= 1 kilometer per 5 minutes
Bike= I kilometer per 2 minutes
3 minutes fast per mile on bike
8 0
4 years ago
If you have a block of wood that is 4cm wide ,6cm long and 10cm high and it weighs 100 grams what would happen to the volume if
n200080 [17]
It would make both half 4cm to 2cm wide, and 6cm to 3cm long, 10cm to 5cm hight it would split in half
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3 years ago
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An airplane with a speed of 92.3 m/s is climbing upward at an angle of 51.1 ° with respect to the horizontal. When the plane's a
devlian [24]

Answer:

a

D =  1162.7 \  m

b

\beta =- 65.55^o

Explanation:

From the question we are told that

  The speed of the airplane is  u  =  92.3 \ m/s

   The  angle is  \theta = 51.1^o

    The altitude of the plane is  d =  532 \  m

Generally the y-component of the airplanes velocity is  

       u_y  =  v *  sin (\theta )

=>     u_y  =   92.3 *  sin ( 51.1 )

=>     u_y  =  71.83  \ m/s

Generally the displacement  traveled by the package in the vertical direction is

       d =  (u_y)t +  \frac{1}{2}(-g)t^2

=>       -532  = 71.83 t +  \frac{1}{2}(-9.8)t^2

Here the negative sign for the distance show that the direction is along the negative y-axis

 =>   4.9t^2 - 71.83t - 532 = 0

Solving this using quadratic formula we obtain that

    t =  20.06 \  s

Generally the x-component of the velocity is  

     u_x  =  u  *  cos (\theta)

=>    u_x  =   92.3  *  cos (51.1)

=>   u_x  =   57.96 \ m/s

Generally the distance travel in the horizontal  direction is    

     D =  u_x  *  t

=>   D =  57.96  *   20.06

=>    D =  1162.7 \  m

Generally the angle of the velocity vector relative to the ground is mathematically represented as

       \beta  =  tan ^{-1}[\frac{v_y}{v_x } ]

Here v_y is the final  velocity of the package along the vertical  axis and this is mathematically represented as  

     v_y  =  u_y  -   gt

=>  v_y  =  71.83  -    9.8 *  20.06

=>  v_y  =  -130.05 \  m/s  

and  v_x is the final  velocity of the package which is equivalent to the initial velocity u_x

So

       \beta  =  tan ^{-1}[-130.05}{57.96 } ]

       \beta =- 65.55^o

The negative direction show that it is moving towards the south east direction

   

6 0
3 years ago
Can anyone explain<br>if knows​
Aleks [24]

Answer:

Sry I’m just trying to get my points :(

Explanation:

Better luck nest time I would help if I was smart enough but currently I’m as d u m b as a rock...

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3 years ago
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