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Delicious77 [7]
3 years ago
6

The siren on an ambulance emits a sound of frequency 2.80×103Hz. If the ambulance is traveling at 26.0 m/s (93.6 km/h or 58.2 mi

/h) the speed of sound is 340 m/s and the air is still, what is the frequency that you hear if you are standing in front of the ambulance?
Physics
1 answer:
Norma-Jean [14]3 years ago
5 0

To solve this problem it is necessary to apply the concepts related to the described wavelength through frequency and speed. Mathematically it can be expressed as:

\lambda = \frac{v}{f}

Where,

\lambda = Wavelength

f = Frequency

v = Velocity

Our values are given as,

f = 2.8*10^3Hz

v = 340m/s \rightarrow Speed of sound

Keep in mind that we do not use the travel speed of the ambulance because we are in front of it. In case it approached or moved away we should use the concepts related to the Doppler effect:

Replacing we have,

\lambda = \frac{340}{2.8*10^3}

\lambda = 0.1214m

Therefore the frequency that you hear if you are standing in from of the ambulance is 0.1214m

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natita [175]

Answer:

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h = 0.86 cm

Part b)

Level will increase

Explanation:

Part a)

Mass of the ice cube is 0.200 kg

Now from the buoyancy force formula we know that weight of the ice is counter balanced by buoyancy force on the ice

So here we will have

mg = \rho V_{displaced} g

V_{displaced} = \frac{m}{\rho}

V_{displaced} = \frac{0.200}{1260} = 1.59 \times 10^{-4} m^3

now as we know that ice will melt into water

so here volume of water that will convert due to melting of ice is given as

V\rho_w = m_{ice}

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So here extra volume that rise in the level will be given as

\Dleta V = V - V_{displaced}

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Part b)

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