7. Thermal energy is the

Which of the following describes gamma rays?

Anarel [89]

Answer: short wavelength, high frequency

Explanation:

Gamma rays are highly energetic electromagnetic waves. High energy implies high frequency.

E = h ν

h is the Planck's constant, ν is the frequency.

For electromagnetic radiation, frequency is inversely proportional to wavelength. Thus, gamma rays have high frequency but short wavelength.

The frequency of gamma rays is greater than 10¹⁹ Hz and wavelength is less 10⁻¹² m.

3 0

2 years ago

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The chemical symbol for sulfuric acid is H2SO4. How many atoms are contained in each molecule of sulfuric acid?

cricket20 [7]

You know from looking at the molecular formula that one molecule of H2SO4 contains 2 atoms of hydrogen, 1 atom of sulfur and 4 atoms of oxygen.

5 0

3 years ago

A 19 g bullet is fired into the bob of a ballistic pendulum of mass 1.3 kg. When the bob is at its maximum height, the strings m

katovenus [111]

Answer:

217.43298 m/s

Explanation:

$m_1$ = Mass of bullet = 19 g

$m_2$ = Mass of bob = 1.3 kg

L = Length of pendulum = 2.3 m

$\theta$ = Angle of deflection = 60°

u = Velocity of bullet

Combined velocity of bullet and bob is given by

$v^2-u^2=2as\\\Rightarrow v=\sqrt{2aL(1-cos\theta)+u^2}\\\Rightarrow v=\sqrt{2\times 9.81\times (1-cos60)+0^2}\\\Rightarrow v=3.13209\ m/s$

As the momentum is conserved

$m_1u=(m_1+m_2)v\\\Rightarrow u=\frac{(m_1+m_2)v}{m_1}\\\Rightarrow v=\frac{(0.019+1.3)\times 3.13209}{0.019}\\\Rightarrow v=217.43298\ m/s$

The speed of the bullet is 217.43298 m/s

5 0

3 years ago

g You shine orange laser light that has a wavelength of 600 nm through a narrow slit. The slit forms a diffraction pattern on a

zimovet [89]

Answer:

λ = 3 10⁻⁷ m, UV laser

Explanation:

The diffraction phenomenon is described by the expression

a sin θ = m λ

let's use trigonometry

tan θ = y / L

as in this phenomenon the angles are small

tan θ = $\frac{sin \ \theta}{cos \ \theta}$ = sin θ

sin θ = y / L

we substitute

a y / L = m λ

let's apply this equation to the initial data

a 0.04 / L = 1 600 10⁻⁹

a / L = 1.5 10⁻⁵

now they tell us that we change the laser and we have y = 0.04 m for m = 2

a 0.04 / L = 2 λ

a / L = 50 λ

we solve the two expression is

1.5 10⁻⁵ = 50 λ

λ = 1.5 10⁻⁵ / 50

λ = 3 10⁻⁷ m

UV laser

3 0

2 years ago

In an experiment, a shearwater (a seabird) was taken from its nest, flown a distance 5220 km away, and released. It found its wa

Korolek [52]

Answer:

4.6834625323 m/s

0 m/s

Explanation:

s = Displacement

t = Time

Velocity is given by

$v=\dfrac{s}{t}\\\Rightarrow v=\dfrac{5220000}{12.9\times 24\times 60\times 60}\\\Rightarrow v=4.6834625323\ m/s$

The bird's average velocity for the return flight is 4.6834625323 m/s

In the whole episode the bird went 5220 km away from its nest and came back. This means the displacement is zero.

Hence, the average velocity for the whole episode is 0 m/s

7 0

3 years ago

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