All categories

2 years ago

HELP I'll MARK BRAINLY

Physics

2 answers:

AURORKA [14]2 years ago

8 0

Answer:

it is plate tectonics option D hope it helps

there are 7 major and 20 minor plates

hichkok12 [17]2 years ago

8 0

I know someone else answered but yes it’s plate tectonics

You might be interested in

At temperatures above roughly 800 °c, calcium carbonate will decompose. write and balance the equation for this reaction. phase

Lady_Fox [76]

CaCO3 ----> CaO + CO2

hope it helps!

8 0

3 years ago

Read 2 more answers

In which states of matter will a substance have a fixed volume?

NISA [10]

Answer:

A. liquid and solid

Explanation:

7 0

2 years ago

Your physics teachers want to race each other using wagon rockets.

Genrish500 [490]

Answer:

s=1/2at^2

s=1/2 x 4 x(10)^2=200m

5 0

2 years ago

A Carnot engine operates between 1350 °F and 125 °F. If it rejects 55 Btu as heat, determine the work output.

ruslelena [56]

Answer:

C. $W = 115.12\,Btu$

Explanation:

Thermodynamically speaking, a Carnot engine represents an entirely reversible thermal process and its energy efficiency represents the maximum theoretical efficiency that thermal machines can reach. The efficiency of the ideal thermal process ( $\eta$ ), no unit, is:

$\eta = \left(1-\frac{T_{L}}{T_{H}} \right)$ (1)

Where:

$T_{L}$ - Temperature of the cold reservoir, measured in Rankine.

$T_{H}$ - Temperature of the hot reservoir, measured in Rankine.

If we know that $T_{H} = 1809.67\,R$ and $T_{L} = 584.67\,R$ , then the energy efficiency of the ideal thermal process is:

$\eta = 0.678$

By First Law of Thermodynamics, we calculate the work output:

$W = Q_{H}-Q_{L}$

$W = \frac{W}{\eta} -Q_{L}$ (By definition of efficiency)

$Q_{L} = \frac{W}{\eta}-W$

$Q_{L} = \left(\frac{1}{\eta}-1 \right)\cdot W$ (2)

Where:

$Q_{H}$ - Heat received by the engine, measured in Btu.

$Q_{L}$ - Heat rejected by the engine, measured in Btu.

$W$ - Work output, measured in Btu.

If we know that $\eta = 0.678$ and $Q_{L} = 55\,Btu$ , then the work output of the Carnot engine is:

$W = \frac{Q_{L}}{\frac{1}{\eta}-1 }$

$W = 115.807\,Btu$

The work output of the Carnot engine is 115.807 Btu. (Answer: C)

5 0

3 years ago

Technician A says that if starter drive clearance is too small, the starter will produce a noise during cranking. Technician B s

Ronch [10]

Answer:

Both Technicians A and B are wrong in there answers.

Explanation:

Starter Drives are rotating mechanical component use to drive another component (flywheel) to start an engine. And thus they are known as starters. Starters are smaller than the component they drive. They are found commonly in automobiles.

The starter and the driven component(gear) are supposed to fit closely, with some clearance between the two gears so as to operate without noise. When the clearance is too small there will be a noise after cranking, and when the clearance is too great there be noise before cranking.

Cranking simply means starting an engine or the initial rotating of an engine to start it.

8 0

3 years ago