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stepan [7]
3 years ago
9

Electrons returning to the ground state from varying excited states always:

Physics
1 answer:
Nuetrik [128]3 years ago
4 0
Emit radiation exactly equal in energy, to the energy difference between states.
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A uniformly charged sphere has a potential on its surface of 450 V. At a radial distance of 7.2 m from this surface, the potenti
Yakvenalex [24]

Answer:

The radius of the sphere is 3.6 m.

Explanation:

Given that,

Potential of first sphere = 450 V

Radial distance = 7.2 m

If the potential of sphere =150 V

We need to calculate the radius

Using formula for potential

For 450 V

V=\dfrac{kQ}{r}

450=\dfrac{kQ}{r}....(I)

For 150 V

150=\dfrac{kQ}{r+7.2}....(II)

Divided equation (I) by equation (II)

\dfrac{450}{150}=\dfrac{\dfrac{kQ}{r}}{\dfrac{kQ}{r+7.2}}

3=\dfrac{(r+7.2)}{r}

3r=r+7.2

r=\dfrac{7.2}{2}

r=3.6\ m

Hence, The radius of the sphere is 3.6 m.

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3 years ago
The catapults on the uss george h.w. bush can launch aircraft from rest to a speed of 150 mph over a distance of 270 feet. find
vlabodo [156]
Hope this helps, have a great day ahead!

8 0
3 years ago
Which of the following processes charges an object by friction
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An example is when u rub your pen on your hair hard that is friction
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Please help me with this question, especially the angle part. I have solved the initial velocity already. I don't know what to d
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I think you almost got it.

At the top, the velocity only has horizontal component, so v=12 m/s is v_x, which is v*cos(theta), because v_x is constant, so the same when it was launched or now.

With the value of the initial speed (28 m/s, which is the total speed), you can set

v_x = v * cos( theta ) ---> 12 = 28*cos(theta) --> cos(theta)=12/28=3/7

or theta = 64.62 deg, it is D. Think about it. I hope you see it.
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5Newtons or 5N

Ten newtons minus five Newton’s is 5 Newton’s
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