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vitfil [10]
3 years ago
11

write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (3,7)

Mathematics
1 answer:
mario62 [17]3 years ago
8 0
Slope intercept form is y=mx+b

y= m or 2 because that is your slope but now all you need to is find your begin or find the point (3,7) on the graph.                
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Which description could be written as a linear function?
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The instruction booklet for a CD player says that the player uses about 0.2 kilowatt of electricity per hour. If electricity cos
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Is y=4x-1 and 12x=3y+7 parallel, perpendicular, or neither
valina [46]
First, you simplify 12x=3y+7. Subrtact 7 from both side, get 12x-7=3y. Divide 3 from both sides, get y=4x-(7/3). Your 2 equations are y=4x-1 and y=4x-7/3. The 2 lines are parallel, since they have the same slope but different b's.
5 0
3 years ago
Read 2 more answers
Square root of 144 X^7 Y^5
LekaFEV [45]
The first step to solving this is to factor out the first perfect square
\sqrt{12^{2} x^{7} y^{5}   }
now factor out the second perfect square
\sqrt{ 12^{2} x^{6} X x  y^{5}  }
then factor out the second perfect square 
\sqrt{ 12^{2}  x^{6} X x  y^{4} X y}
the root of a product is equal to the product of the roots of each factor
\sqrt{ 12^{2} } \sqrt{ x^{6} } \sqrt{ y^{4} } \sqrt{xy}
reduce the index of the radical and exponent with 2 of the first square root
12\sqrt{ x^{6} } \sqrt{ y^{4} } \sqrt{xy}
reduce the index of the radical and exponent with 2 of the second square root
12x³\sqrt{ y^{4} } \sqrt{xy}
reduce the index of the radical and exponent with 2 of the third square root
12x³y²\sqrt{xy}
this means that the correct answer to your question is 12x³y²\sqrt{xy} .
let me know if you have any further questions
:)
4 0
3 years ago
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