<em>Greetings from Brasil...</em>
Here we will apply rule of 3...
This formula, A = πR², its for the whole circle, that is, 360° (2π)
We want the area of only a part, that is, a circular sector whose angle π/6
sector area
2π ----- πR²
π/6 ----- X
2πX = (π/6).πR²
2πX = π²R²/6
X = π²R²/12π
<h3>X = πR²/12</h3>
If Ronisha multiply the area by 1/12 she will get the area of sector with angle of π/6
N= -20/133
Step 1: Simplify both sides of the equation.
−
2
(
−
4
n
+
1
)
+
5
(
25
n
−
8
)
=
−
62
(
−
2
)
(
−
4
n
)
+
(
−
2
)
(
1
)
+
(
5
)
(
25
n
)
+
(
5
)
(
−
8
)
=
−
62
(Distribute)
8
n
+
−
2
+
125
n
+
−
40
=
−
62
(
8
n
+
125
n
)
+
(
−
2
+
−
40
)
=
−
62
(Combine Like Terms)
133
n
+
−
42
=
−
62
133
n
−
42
=
−
62
Step 2: Add 42 to both sides.
133
n
−
42
+
42
=
−
62
+
42
133
n
=
−
20
Step 3: Divide both sides by 133.
133
n
133
=
−
20
133
n
=
−
20
133
Answer:
Step-by-step explanation:
$12(20b/$48)=5b
Y = 3x + 1
Parallel lines have the same slope so the slope would be 3. Take the given equation and add the 3x to the other side. Using the given point. -2 (y point) = 3(-1(x point)) + b. Solve for b by adding the 3 over. b = 1 which is your y intercept.
