The difference of two numbers is 40. Their sum is 66. Find the numbers.
2 answers:
First of all, x>y
x-y=40
and
x+y=66
add them equations together to eliminate
x-y=40
<u>x+y=66 +</u>
2x+0y=106
2x=106
divide by 2
x=53
sub back
x-y=40
53-y=40
minus 53 both sides
-y=-13
y=13
the numbers are 53 and 13
53-13 equals 40 and 13+53 is 66
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Step-by-step explanation:
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13RO = 513
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Answer:
<h2>s = 66</h2>
Step-by-step explanation:
s + 24 = 90 <em>subtract 24 from both sides</em>
s + 24 - 24 = 90 - 24
s = 66
Answer:
Option C(66.0)
Step-by-step explanation:
C = 2πr
C=Circumference
π=3.14(pi)
r=radius
C=2x3.14x10.5
3.14x10.5=32.97
32.97x2=65.94
65.94 rounded to nearest tenth is 65.9, so basically 66.0.
