Answer:

Step-by-step explanation:
When you reflect a point (x, y) in the y-axis, the y-coordinate remains the same, but the x-coordinate gets the opposite sign. Thus,
E (8,4) ⟶ E' (-8,4)
F (-16,-8) ⟶ F' (16,-8)
G (24,-16) ⟶ G' (-24,-16)

The figure EFG and its reflection E'F'G' are shown in the diagram below.
Some things you need to know:
1) You need to know how to convert standard form to slope y-int. form and slope y-int. form to standard form.
2) When two lines are parallel, the slopes are the same.
3) When two lines are perpendicular, the slopes are negative reciprocals of each other. (Or their product is -1)
example: 3/4 --> -4/3.
3/4 * -4/3 = -12/12 = -1
4) To find the value of b, substitute the point into the equation.
5) Convert the equation to slope y-int. form to find the slope.
6) When a line has an undefined slope, the slope y-int. will look either like
y = __ (forms horizontal line) or x = __ (forms vertical line).
To find the perpendicular of these lines, turn y to x / x to y.
To find the value of __, look at the point located in the line, so if x = ___
passes through (5,3), then x = 5 because x = 5 in the point. So the
equation would be x = 5.
Use online practice tests and other sources if you don't understand.
Answer:
I dont know im really sorry
Harold paid $ 16,632 and $ 38,808 for each of the boats.
Since Harold, a marina manager, purchased two boats, and he then sold the boats, the first at a profit of 40% and the second at a profit of 60%, and the total profit on the sale of the two boats was 54 % and $ 88 704 was the total selling price of the two boat, to determine what did Harold originally pay for each of the two boats the following calculation must be performed:
- 55 x 0.6 + 45 x 0.4 = 51
- 65 x 0.6 + 35 x 0.4 = 53
- 70 x 0.6 + 35 x 0.4 = 54
- 88,704 x 0.7 = 62,092.80
- 160 = 62,092.80
- 100 = X
- 100 x 62,092.80 / 160 = X
- 38.808 = X
- 88,704 x 0.3 = 26,611.20
- 140 = 26,611.20
- 100 = X
- 100 x 26,611.20 / 160 = X
- 16,632 = X
Therefore, Harold paid $ 16,632 and $ 38,808 for each of the boats.
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