Answer:
a² + 2ah + 3a + 3h + 5 + h²
Step-by-step explanation:
to evaluate f(a + h) substitute x = a + h into f(x)
f(a + h)
= (a + h)² + 3(a + h) + 5 ← distribute
= a² + 2ah + h² + 3a + 3h + 5
Let us assume the cost of 1 apple = x dollars
Let us also assume the cost of 1 pear = y dollars
Then we can form two equations from the details given in the question. Based on those details the required answer to the question can be easily deduced.
3x + 8y = 14.50
And
6x + 4y = 14
Dividing both sides of the equation by 2 we get
3x + 2y = 7
2y = 7 - 3x
y = (7 - 3x)/2
Putting the value of y from the second equation in the first equation we get
3x + 8y = 14.50
3x + 8[(7 - 3x)/2] = 14.50
3x + 4 (7 - 3x) = 14.50
3x + 28 - 12x = 14.50
- 9x = 14.50 - 28
- 9x = - 13.5
9x = 13.5
x = 13.5/9
= 1.5
Putting the value of x in the second equation we get
6x + 4y = 14
(6 * 1.5) + 4y = 14
9 + 4y = 14
4y = 14 - 9
4y = 5
y = 5/4
= 1.25
So we can find from the above deduction that the cost of 1 apple is 1.5 dollars and the cost of 1 pear is 1.25 dollars
Then
Cost of 2 apples = 2 * 1.5 dollars
= 3.0 dollars
So the cost of 2 apples is $3 and the cost of 1 pear is $1.25.
Since the area is 120 ft^2, and we know the length of the room is 15 ft, we can calculate the width.
120/15 = 8
To find the perimeter, we use the following formula
2l + 2w = P
2 (15) + 2 (8) = 46 ft
Answer:
The minor arc HK is 60 degrees
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
The inscribed angle is half that of the arc it comprises.
so

we have

substitute the given value


Remember that the measure of the minor arc must be less than 180 degrees
therefore
The minor arc HK is 60 degrees
Let x be the resistance of the wire with the larger diameter.
x = (0.456 x (0.01)^2)/(0.0401)^2 = 0.0284 ohms
The answer is 0.0284 ohms.