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BaLLatris [955]
2 years ago
12

The diagonals of square ABCD intersect at point E. If BE = 2x + 1, and AC = 3(6x - 4), find BD.

Mathematics
2 answers:
Masteriza [31]2 years ago
8 0

Answer:

It is 6

Step-by-step explanation:

I did the problem already

Butoxors [25]2 years ago
4 0

Answer:

Step-by-step explanation:

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\displaystyle\iiint_R\mathrm dV=\int_{y=-7}^{y=7}\int_{x=-\sqrt{49-y^2}}^{x=0}\int_{z=x}^{z=0}\mathrm dz\,\mathrm dx\,\mathrm dy

Converting to cylindrical coordinates, the integral is equivalent to

\displaystyle\iiint_R\mathrm dV=\int_{\theta=\pi/2}^{\theta=3\pi/2}\int_{r=0}^{r=7}\int_{z=r\cos\theta}^{z=0}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta
=\displaystyle\int_{\theta=\pi/2}^{\theta=3\pi/2}\int_{r=0}^{r=7}-r^2\cos\theta\,\mathrm dr\,\mathrm d\theta
=-\displaystyle\left(\int_{\theta=\pi/2}^{3\pi/2}\cos\theta\,\mathrm d\theta\right)\left(\int_{r=0}^{r=7}r^2\,\mathrm dr\right)
=\dfrac{2\times7^3}3=\dfrac{686}3
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3 years ago
Help please! any help is appreciated
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Step-by-step explanation:

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