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Alika [10]
2 years ago
9

What is the average rate of change for this quadratic function for the interval

Mathematics
1 answer:
Romashka [77]2 years ago
7 0

Answer:

x 2 − 8 x + 15

Step-by-step explanation:

( x − 3 ) ( x− 5)

 Expand  ( x − 3 ) ( x − 5 )

using the FOIL Method.

x ⋅ x + x ⋅ − 5 − 3 x − 3 ⋅ − 5

Simplify and combine like terms.

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Let ????C be the positively oriented square with vertices (0,0)(0,0), (2,0)(2,0), (2,2)(2,2), (0,2)(0,2). Use Green's Theorem to
bonufazy [111]

Answer:

-48

Step-by-step explanation:

Lets call L(x,y) = 10y²x, M(x,y) = 4x²y. Green's Theorem stays that the line integral over C can be calculed by computing the double integral over the inner square  of Mx - Ly. In other words

\int\limits_C {L(x,y)} \, dx + M(x,y) \, dy =  \int\limits_0^2\int\limits_0^2 (M_x - L_y ) \, dx \, dy

Where Mx and Ly are the partial derivates of M and L with respect to the x variable and the y variable respectively. In other words, Mx is obtained from M by derivating over the variable x treating y as constant, and Ly is obtaining derivating L over y by treateing x as constant. Hence,

  • M(x,y) = 4x²y
  • Mx(x,y) = 8xy
  • L(x,y) = 10y²x
  • Ly(x,y) = 20xy
  • Mx - Ly = -12xy

Therefore, the line integral can be computed as follows

\int\limits_C {10y^2x} \, dx + {4x^2y} \,dy = \int\limits_0^2\int\limits_0^2 -12xy \, dx \, dy

Using the linearity of the integral and Barrow's Theorem we have

\int\limits_0^2\int\limits_0^2 -12xy \, dx \, dy = -12 \int\limits_0^2\int\limits_0^2 xy \, dx \, dy = -12 \int\limits_0^2\frac{x^2y}{2} |_{x = 0}^{x=2} \, dy = -12 \int\limits_0^22y \, dy \\= -24 ( \frac{y^2}{2} |_0^2) = -24*2 = -48

As a result, the value of the double integral is -48-

3 0
3 years ago
A ratio of a TV's width to its height is 16:9. If its width is 32 inches, what is the length of its diagonal? Give your answer t
Katarina [22]

Answer:

36.7

Step-by-step explanation:

7 0
2 years ago
Find the measure of angle A
Mariana [72]
Apply the law of cosines. and solve for A

14^{2} = 11^{2} + 11^{2} - 2(11)(11)cos(A) \\ 
196 = 121 + 121 - 242cos(A)  \\ 
-46 = -242cos(A) \\cos(A) = 0.1900826446

 A = 79.04239272, or 79

5 0
3 years ago
I need help I have 20 min
Bezzdna [24]

Answer:

1- d

2- a

3- d

4- b

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Greg and Heather each opened a savings account today. Greg opened his account with a starting amount of $330, and he is going to
cluponka [151]

Set up two equations:

Greg = 330 + 75X

Heather = 660 + 45x

Set them to equal and solve for x:

330 + 75x = 660 + 45x

Subtract 330 from both sides:

75x = 330 + 45x

Subtract 45x from both sides:

30x = 330

Divide both sides by 30:

x = 330 / 30

X = 11

11 months they will have the same amount saved.

6 0
3 years ago
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