What is the average rate of change for this quadratic function for the interval
1 answer:
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Answer:
Step-by-step explanation:
From Bayes' theorem is stated mathematically as the following equation:[2]
{\displaystyle P(A\mid B)={\frac {P(B\mid A)\,P(A)}{P(B)}},}
where A and B are events and P(B) ≠ 0.
P(A) and P(B) are the probabilities of observing A and B without regard to each other.
P(A | B), a conditional probability, is the probability of observing event A given that B is true.
P(B | A) is the probability of observing event B given that A is true.
At this point, go through the attached file before you continue with part B.
Part B)
P(silver) = P(silver from SS)+P(silver from GS)
note P(SS)=P(GG)=P(GS) = 1/3
P(silver from SS) = 1
P(silver from GS) = 1/2
hence
P(Silver from SS) = 1/3
P(Silver from GS) = 1/3 *1/2
P(Silver) = 1/3*1+1/3*1/2
required probability = P(Silver from SS)/P(Silver) = 2/3
Anwers:
1. line A
2. line D
3. line B
4. line C
Step-by-step explanation:
I think your question is missed of key information, allow me to add in and hope it will fit the original one.
Please have a look at the attached photo.
My answer:
Given the original function:
f(x) = 10x
and g(x) = a · 10x is the general from of all transformed functions from the above original function.
- p(x) = 4 · 10x
The graph of this function is stretched vertically => line A
- q(x) = –4 · 10x
The graph of this function is stretched vertically and is reflected through the x-asix => line D.
- r(x) = (1/4) x 10x
The graph of this function is compressed vertically => line B
- s(x) = (-1/4) x 10x
The graph of this function is compressed vertically and is reflected through the x-asix => line C
Hope it will find you well.
