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Alika [10]
2 years ago
9

What is the average rate of change for this quadratic function for the interval

Mathematics
1 answer:
Romashka [77]2 years ago
7 0

Answer:

x 2 − 8 x + 15

Step-by-step explanation:

( x − 3 ) ( x− 5)

 Expand  ( x − 3 ) ( x − 5 )

using the FOIL Method.

x ⋅ x + x ⋅ − 5 − 3 x − 3 ⋅ − 5

Simplify and combine like terms.

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Calculate the volume of the following object:
frozen [14]

Answer:

262.44 cubic metres.

Step-by-step explanation:

First, we can calculate the volume of the cylinder by doing pi * r^2 * h. In this case, r is 5 / 2 and h is 7.

pi * (5/2)^2 * 7 = pi * 25/4 * 7 = pi * 6.25 * 7 = pi * 43.75 = 3.14159265 * 43.75 = 137.4446784 cubic m.

Seconds, we calculate the volume of the cube. It is 5^3 = 5 * 5 * 5 = 25 * 5 = 125 cubic m.

137.4446784 + 125 = 262.4446784, which is about 262.44 cubic metres.

Hope this helps!

3 0
3 years ago
Read 2 more answers
The object on the right is made from a square-based pyramid joined to a cuboid.
spayn [35]

Answer:

Density of steel = 80.73 gm/cm^3

Step-by-step explanation:

The figure is made up of cuboid and square pyramid.

Height of cuboid, h = 9 cm

Length of cuboid, l = 6 cm

Width of cuboid, w = 6 cm

Volume of cuboid is given by the formula:

V_{Cuboid} = l \times w \times h

V_{Cuboid} = 6 \times 6 \times 9\\\Rightarrow V_{Cuboid} = 324\ cm^3

Density of Wood , D_{Cuboid}= 0.68g/cm^3

We know that formula of Density is:

Density = \dfrac{Weight}{Volume}

D_{Cuboid} = \dfrac{W_{Cuboid}}{V_{Cuboid}}\\\Rightarrow W_{Cuboid} = V_{Cuboid} \times D_{Cuboid}

Putting the values:

W_{Cuboid} = 324 \times 0.68 = 220.32\ gm

Total weight = W_{Cuboid} + W_{Pyramid}

970 = 220.32 + W_{Pyramid}

W_{Pyramid} = 749.68 gm

Volume of pyramid is given as:

V_{Pyramid}= \dfrac{1}{3} \times \text{Area of Base} \times \text{Vertical Height}

Base is a square with side 6 cm

V_{Pyramid}= \dfrac{1}{3} \times 6 \times 6 \times (17 -9)\\V_{Pyramid}= 96\ cm^3

Density of Steel/Pyramid:

D_{Pyramid} = \dfrac{W_{Pyramid}}{V_{Pyramid}}\\\Rightarrow D_{Pyramid} = \dfrac{749.68}{96}\\\Rightarrow D_{Pyramid} = 80.73\ gm/cm^3

5 0
3 years ago
Find the X and Y intercept of line 2x+3y=-12<br><br> X-intercept -<br><br> Y- Intercept-
vivado [14]

Answer:

  • Let us rearrange
  • 3y=-2x-12
  • y=-2/3x-4
  • So y intercept is -4
  • I also do exams and quizzes if your interested :)
7 0
2 years ago
It rained 2.79 inches in july. what was the average daily rainfall in july
Murrr4er [49]
Theres not enough information to properly answer this.

3 0
3 years ago
Read 2 more answers
The endpoints of CD are C(–8, 4) and D(6, –6). What are the coordinates of point P on CD such that P is the length of the line s
GalinKa [24]
If you graph the end points C and D then graph the 4 points at the end it is difficult to tell which points are on CD without a line.  
Using the endpoints find the slope (change in y/ change in x) then substitute a point in to find the intercept.  
Slope = (-6-4)/(6- -8) = -5/7
Intercept equation (-6) = -5/7 (6) + b
b = -1.71428571429
Graphing the line shows only 2 points on the line (–2.75, 0.25) and <span>(0.75, –2.25)
I am confused by the part, "</span><span>P is the length of the line segment from D".  Were you given a length P to help you determine which point.  Using the distance formula to find the length from each point to D doesn't help determine which one is best with the information you have given.  The image shows the distances I calculated and the graphed points. 
I hope this helps!</span>

5 0
2 years ago
Read 2 more answers
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