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2 years ago

What is the average rate of change for this quadratic function for the interval

Mathematics

1 answer:

Romashka [77]2 years ago

7 0

Answer:

x 2 − 8 x + 15

Step-by-step explanation:

( x − 3 ) ( x− 5)

Expand ( x − 3 ) ( x − 5 )

using the FOIL Method.

x ⋅ x + x ⋅ − 5 − 3 x − 3 ⋅ − 5

Simplify and combine like terms.

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Calculate the volume of the following object:

frozen [14]

Answer:

262.44 cubic metres.

Step-by-step explanation:

First, we can calculate the volume of the cylinder by doing pi * r^2 * h. In this case, r is 5 / 2 and h is 7.

pi * (5/2)^2 * 7 = pi * 25/4 * 7 = pi * 6.25 * 7 = pi * 43.75 = 3.14159265 * 43.75 = 137.4446784 cubic m.

Seconds, we calculate the volume of the cube. It is 5^3 = 5 * 5 * 5 = 25 * 5 = 125 cubic m.

137.4446784 + 125 = 262.4446784, which is about 262.44 cubic metres.

Hope this helps!

3 0

3 years ago

Read 2 more answers

The object on the right is made from a square-based pyramid joined to a cuboid.

spayn [35]

Answer:

Density of steel = 80.73 gm/ $cm^3$

Step-by-step explanation:

The figure is made up of cuboid and square pyramid.

Height of cuboid, h = 9 cm

Length of cuboid, l = 6 cm

Width of cuboid, w = 6 cm

Volume of cuboid is given by the formula:

$V_{Cuboid} = l \times w \times h$

$V_{Cuboid} = 6 \times 6 \times 9\\\Rightarrow V_{Cuboid} = 324\ cm^3$

Density of Wood , $D_{Cuboid}$ = 0.68g/ $cm^3$

We know that formula of Density is:

$Density = \dfrac{Weight}{Volume}$

$D_{Cuboid} = \dfrac{W_{Cuboid}}{V_{Cuboid}}\\\Rightarrow W_{Cuboid} = V_{Cuboid} \times D_{Cuboid}$

Putting the values:

$W_{Cuboid} = 324 \times 0.68 = 220.32\ gm$

Total weight = $W_{Cuboid} + W_{Pyramid}$

970 = 220.32 $+ W_{Pyramid}$

$W_{Pyramid}$ = 749.68 gm

Volume of pyramid is given as:

$V_{Pyramid}= \dfrac{1}{3} \times \text{Area of Base} \times \text{Vertical Height}$

Base is a square with side 6 cm

$V_{Pyramid}= \dfrac{1}{3} \times 6 \times 6 \times (17 -9)\\V_{Pyramid}= 96\ cm^3$

Density of Steel/Pyramid:

$D_{Pyramid} = \dfrac{W_{Pyramid}}{V_{Pyramid}}\\\Rightarrow D_{Pyramid} = \dfrac{749.68}{96}\\\Rightarrow D_{Pyramid} = 80.73\ gm/cm^3$

5 0

3 years ago

Find the X and Y intercept of line 2x+3y=-12 X-intercept - Y- Intercept-

vivado [14]

Answer:

Let us rearrange
3y=-2x-12
y=-2/3x-4
So y intercept is -4
I also do exams and quizzes if your interested :)

7 0

2 years ago

It rained 2.79 inches in july. what was the average daily rainfall in july

Murrr4er [49]

Theres not enough information to properly answer this.

3 0

3 years ago

Read 2 more answers

The endpoints of CD are C(–8, 4) and D(6, –6). What are the coordinates of point P on CD such that P is the length of the line s

GalinKa [24]

If you graph the end points C and D then graph the 4 points at the end it is difficult to tell which points are on CD without a line.
Using the endpoints find the slope (change in y/ change in x) then substitute a point in to find the intercept.
Slope = (-6-4)/(6- -8) = -5/7
Intercept equation (-6) = -5/7 (6) + b
b = -1.71428571429
Graphing the line shows only 2 points on the line (–2.75, 0.25) and (0.75, –2.25)
I am confused by the part, "P is the length of the line segment from D". Were you given a length P to help you determine which point. Using the distance formula to find the length from each point to D doesn't help determine which one is best with the information you have given. The image shows the distances I calculated and the graphed points.
I hope this helps!

5 0

3 years ago

Read 2 more answers