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2 years ago

Finance literacy I want to withdraw 400.00 for 9 years at 8%. How much do I need to deposit

Mathematics

1 answer:

neonofarm [45]2 years ago

5 0

Answer:

Up-to-date rates are available from finance organisations. ... What is the actual rate of interest if £4000 deposited for 3 years attracts interest of ... What amount will you have to pay back?

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a refrigerator can be bought on credit for $5000. the store wants a down payment of $50. the balance is to be paid over 2 years.

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3 years ago

Priya says the area of the large unmarked square is 26 square units because: 9+17=26. Do you agree with Priya?

Rudik [331]

Nope because she only used two of the net faces

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3 years ago

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6. If the net investment function is given by

Pachacha [2.7K]

The capital formation of the investment function over a given period is the

accumulated capital for the period.

(a) The capital formation from the end of the second year to the end of the fifth year is approximately 298.87.

(b) The number of years before the capital stock exceeds $100,000 is approximately 46.15 years.

Reasons:

(a) The given investment function is presented as follows;

$I(t) = 100 \cdot e^{0.1 \cdot t}$

(a) The capital formation is given as follows;

$\displaystyle Capital = \int\limits {100 \cdot e^{0.1 \cdot t}} \, dt =1000 \cdot e^{0.1 \cdot t}} + C$

From the end of the second year to the end of the fifth year, we have;

The end of the second year can be taken as the beginning of the third year.

Therefore, for the three years; Year 3, year 4, and year 5, we have;

$\displaystyle Capital = \int\limits^5_3 {100 \cdot e^{0.1 \cdot t}} \, dt \approx 298.87$

The capital formation from the end of the second year to the end of the fifth year, C ≈ 298.87

(b) When the capital stock exceeds $100,000, we have;

$\displaystyle \mathbf{\left[1000 \cdot e^{0.1 \cdot t}} + C \right]^t_0} = 100,000$

Which gives;

$\displaystyle 1000 \cdot e^{0.1 \cdot t}} - 1000 = 100,000$

$\displaystyle \mathbf{1000 \cdot e^{0.1 \cdot t}}} = 100,000 + 1000 = 101,000$

$\displaystyle e^{0.1 \cdot t}} = 101$

$\displaystyle t = \frac{ln(101)}{0.1} \approx 46.15$

The number of years before the capital stock exceeds $100,000 ≈ 46.15 years.

Learn more investment function here:

brainly.com/question/25300925

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2 years ago

Hey guys what is this type of equation/ question called 1 < x < 30

dimulka [17.4K]

Answer:

2,3,4,5,6,7,8,9,10,...29

Step-by-step explanation:

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3 years ago

Which expression is equivalent to 9^-2? –81 –18 1/81 1/18

Kaylis [27]

(9)^-2 = (1/9)^2 = 1/81

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3 years ago

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