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IgorC [24]
3 years ago
5

Can you still use the Pythagorean theorem to find the missing side length of 45-45-90 and 30-60-90 triangles or do they not work

for these types of right triangles
Mathematics
1 answer:
NeX [460]3 years ago
6 0
Hi there!

If you know the length of two side lengths and need to find the length of the third side length, you can definitely use Pythagorean theorem or inverse Pythagorean theorem to solve, but if you only know the angles of the triangle, you'll heed to use laws of sine, cosine, and tangent. 

Hope this helps!
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Plsss help it also detects if it’s right or wrong
Masteriza [31]

Answer:

3/8

Step-by-step explanation:

Looking at the bottom row, there are 8 possible outcomes

HHH, HHT, HTH, HTT, THH, THT, TTH, TTT

There are 3 that have exactly 2 heads HHT, HTH, THH,

That means the probability is

P( exactly 2 heads) = number outcomes with exactly 2 heads/total outcomes

                                 =3/8

7 0
3 years ago
Please can i have some help, just on this question, thank you so much!
Andrew [12]

Answer:

a) 1/2 of 12 = 1/4 of 24

b) 1/3 of 90 = 2/3 of 45

Step-by-step explanation:

1/2 of 16 is 6, so 6 would be 1/4 of what? 6 x 4 = 24. 6 is 1/4 of 24. The other one is the same. 1/3 of 90 is 30, and 30 is 2/3 of 45.

5 0
2 years ago
(I'd like the quick and short answer please a long explaination is unnecessary)
professor190 [17]

Answer:

(-3;-2)

Step-by-step explanation:

5 0
2 years ago
Making and Interpreting Correlations: Mastery Test
garri49 [273]

Answer:

Graph D > Graph A > Graph C > Graph B

Step-by-step explanation:

The closer the data points are to each other along the line of best fit, the greater the value of their correlation coefficient, and vice versa.

Therefore, the graphs can be arranged in descending other (from the highest to the lowest) based on the values of their correlation coefficients as follows:

Graph D > Graph A > Graph C > Graph B

8 0
2 years ago
The density of a fluid is given by the empirical equation rho=70.5 exp(8.27 X 10^-7 P) where rho is density (lbm/ft^3) and P is
jasenka [17]

Answer:

(a) The unit of 70.5 is lbm/ft^3 and the unit of 8.27×10^-7 is in^2/lbf

(b) density = 0.1206g/cm^3

(c) rho = 0.1206exp(8.27×10^-7P)

Step-by-step explanation:

(a) The unit of 70.5 is the same as the unit of rho which is lbm/ft^3. The unit of 8.27×10^-7 is the inverse of the unit of P (lbf/in^2) because exp is found of a constant. Therefore, the unit of 8.27×10^-7 is in^2/lbf

(b) P = 9×10^6N/m^2

rho = 70.5exp(8.27×10^-7× 9×10^6) = 70.5exp7.443 = 70.5×1.71 = 120.6kg/m^3

rho = 120.6kg/m^3 × 1000g/1kg × 1m^3/10^6cm^3 = 0.1206g/cm^3

(c) Formula for rho (g/cm^3) as a function of P (N/m^2) is

rho = 0.1206exp(8.27×10^-7P) (the unit of 0.1206 is g/cm^3)

5 0
3 years ago
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